They will have the same solution because the first equation of system b
is obtained by adding the first equation of system a to 4 times the
second equation of system a.
Answer:
-14c
Step-by-step explanation:
I’m using the actual values 1F = -17C so just times that by 5.4
4. 8
/ \ / \
2 x 2. 4 x 2
/ \
2 x 2
4: 2x2
8: 2x2x2
The GCF is 4
Answer:
The answer is given below
Step-by-step explanation:
The loads in the circuit are continuous duty, so the circuit can only loaded to 80% of its current rating.
Calculate 80% current rating of the circuit breaker.
Icb = [ 80/100] (20 A)
= (O.8) (20 A )
= 16 A
Now we assume that the value of supply voltage is 120 V
Now we will calculate current flows via under water light which will be taken as Load 1
<em>Ii = </em>500 W/120 V
= 4.167 A
Current via the circulating pump which will be taken as Load 2 IS 8.5 A
<em>I = </em>load1 + load 2
<em> = 4.167 A + 8.5 A</em>
<em> = 12.67 A</em>
The total current in the circuit obtained which is less than the circuit breaker rating current. Therefore, the power can be operated for both the loads.
