Answer:
Step-by-step explanation:
To find the first five terms
we come with a1
a(n) = a1 +(n-1)d
a(17) = a1 +(17-1)6=71
So a1=71-96= <u>-25 </u>
first five terms:
a1= -25
a(2) = -25 +(2-1)6=<u>-19</u>
a(3) = -25 +(3-1)6=<u>-13</u>
a(4) = -25 +(4-1)6=<u>-7</u>
a(5) = -25 +(5-1)6=<u>-1</u>
<u>hope it helps</u>
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I believe the answer is D.
3(x+2) = 2(2x+7)
3x + 6 = 4x + 14 (On the left side we distribute 3 through parenthesis and on the right side we do the same with 2)
3x - 4x = 14 - 6 (Here we move 4x from the right to the left side and it changes its sign. We do the same with 6)
-x = 8
x = - 8