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Darya [45]
3 years ago
6

Fiona wrote the linear equation y = x – 5. when henry wrote his equation, they discovered that his equation had all the same sol

utions as fiona’s. which
equation could be henry’s?
Mathematics
2 answers:
djverab [1.8K]3 years ago
6 0
I would go with A but I am not 100% sure so you may want to check however you can.
AleksAgata [21]3 years ago
4 0

Answer with explanation:

The options are

      (A) x- \frac{5 y}{4} =\frac{25}{4}(B) x- \frac{5 y}{2} =\frac{25}{4}(C) x-\frac{5 y}{4} =\frac{25}{2}(D) x-\frac{5 y}{2} =\frac{25}{2}

Equation wrote by ,Fiona is:

    y = x -5

The equation which has same solution that Fiona has written,will be coincident with the equation of line that Fiona has written.

And,Equation of that line will be:

   Multiply equation 1, by any real number , k,where, k≠0.

⇒k y= k x- 5 k

This should be ,equation that had  the same solutions as Fiona’s,where k can take any real number but not 0.

None of the Option

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8(x+3)

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thats the answer

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Please help I don’t wanna add a bunch of points Bc nobody is helping me I’m just wasting them.
Ede4ka [16]

Answer:Cross multiply and solve for x.

x/6 = 5/1.25

let the height of building be h ft

h/6 = 60/15

h = 6(60/15) = 24

the building is 24 ft high

Step-by-step explanation:

Well first let’s covert the ft to in- 5ft is 60 in and 6ft is 72 in. Then we want to set up 2 fractions based on height and shadow, so we have 60/15=x/72 (we put x because that’s what we’re trying to find). Then we do cross multiplication so now we have 15x=4320. We divide 15, so now we have 4320/15=288. So the building is 288 in tall or 24ft tall! Glad to help! :)

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2 years ago
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Alla [95]

Answer:

$15865.6

Step-by-step explanation:

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6 0
3 years ago
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FUNDRAISING A school is raising money by selling calendars for $20 each. Mrs. Hawkins promised a party to whichever of her Engli
____ [38]

Rj, this is the solution to question 19:

• 1st period class sold 60 calendars in total

,

• 2nd period class sold 123 calendars in total

We calculate the average per week, this way:

• 1st period class sold 60/4 = 15 calendars per week

,

• 2nd period class sold 123/4 = 30.75 calendars per week

In consequence the multiplication equation that represents this situation is:

15w + 30.75w = 183, where w is the number of weeks Mrs. Hawkins' classes sold calendars.

This is the solution to question 20:

We already know the average number of calendars that 1st and 2nd period classes sold per week. Now, let's calculate the average for 3nd 4th peiod classes, this way:

• 3rd period class sold 89 calendars in total

,

• 4th period class sold 126 calendars in total

Therefore, the average is:

• 3rd period class sold 89/4 = 22.25 calendars per week

,

• 4th period class sold 126/4 = 31.5 calendars per week

Summarizing, we have:

15 + 30.75 + 22.25 + 31.5 = 99.5 calendars was the average number sold by all her classes in a week.

•

7 0
1 year ago
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