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Vladimir [108]
3 years ago
9

Doors for the small cabinets are 11.5 inches long. Doors for the large cabinets are 2.3 times as long as the doors for the small

cabinets. How many large doors can be cut from a board that is 10 1/2 feet long?
Mathematics
1 answer:
tiny-mole [99]3 years ago
7 0
The size of the large cabinets door = 2.3 * 11.5 = 26.45 inches
the board size in inches = 10 1/2 * 12 = 126 inches
number of doors = 126 / 26.45 = 4.76
so the number of doors = 4 doors
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Simplify: $\frac{1}{\sqrt{2}+\frac{1}{\sqrt{8}+\sqrt{200}+\frac{1}{\sqrt{18}}}}$.
dmitriy555 [2]

Answer:

Step-by-step explanation:

its no way to answer how u texted it

5 0
2 years ago
If I am putting carpet in my basement, how many square feet of carpeting do I need if the room is 20ft.x10ft.?
kogti [31]

It would be: 20* 10 = 200 ft²

so, the carpet should have the area of about 200 ft²

8 0
3 years ago
QUICK EASY 25 POINTS!!
MAVERICK [17]

Answer:

1. leave the radical symbol and don't try to convert it to a decimal form

2. The approximated value differs from the exact solution and doesn't give a true equation.

3. Depending on the case, if she needs a mathematical answer, the exact value should be used, but for more practical applications, the rounded decimal form would be more usable.

Step-by-step explanation:

The step by step solution to the equation:

4x^3=756\\x^3=\frac{756}{4} =189\\x=\sqrt[3]{189} \\x=\sqrt[3]{3^3*7} \\x=3*\sqrt[3]{7}

1.- Exact solution means that if in the final step when solving for x the value of  x^3 is not a perfect cube, one needs to leave it indicated as a radical expression (with the radical symbol).

in our case, the cubic root of 189 is not a perfect cube. The factor form of 189 is: 3^3*7, so there is a perfect cube factor (3^3), but the other factor (7) is a prime number. Therefore 3 can get out of the root, while 7 stays inside.

2.- The equation was solved above, in exact form. Now to solve it giving a decimal approximation, we use a calculator to find the cubic root of 7, which is an irrational number with infinite number of decimals, the first of which we type here: \sqrt[3]{7} = 1.91293118...

Therefore, the decimal approximation to the solving for x would be:

x=3*\sqrt[3]{7}=3*1,91293118...=5.73879...=5.74

Where we rounded to two decimals as requested.

When we replace the exact answer in the original expression, we get a perfect equality:

4*x^3=756\\4* (3\sqrt[3]{7} )^3=756\\4*3^3*(\sqrt[3]{7} )^3=756\\4*27*7=756\\\\756=756

While if we use the approximate answer, we get:

4*x^3=756\\\\4*(5.74)^3=756\\\\4*189.119224=756\\756.476896=756

which is NOT a true equality.

3.- I would stick with the idea of showing the exact answer as answer to the mathematical equation. but for a practical case (for example she needs to by some material as a result of her equation solving, it would be more practical to take the numerical approximation to the store, instead of a cubic root of a number.

7 0
3 years ago
Question 10(Multiple Choice Worth 1 points)
Mila [183]
Answer:
—6

Explanation:
In an expression with a negative number and a positive number, the negative will come on top. This meaning the product (end piece) will be negative. In this problem despite the signs we know 3•2 is 6. Now since one number is negative (3) and the other is positive (2) negative will come out on top.

* KEEP IN MIND *
+ and + = positive
- and + = negative

Easy Memo for Multiplication and Divison:
“Same sign add, different sign subtract”
Add = Positive (+)
Subtract = Negative (-)
8 0
3 years ago
If the mass of a material is 45 grams and the volume of the material is 11 cm^3, what would the density of the material be?
Nuetrik [128]

Answer:

Density of material would be 4.09 g/cm^3

units is g/cm^3

Step-by-step explanation:

Given: The mass of a material is 45 grams and the volume of the material is 11 cubic centimeter

Density is defined as mass per unit volume.

It is given by:

p= \frac{m}{V} where p is the density , m is the mass and V is the volume of the material respectively.

Here, Density is expressed in grams per centimeter cubed (g/cubic cm)

Here, m = 45 g , V = 11 cubic cm

We get;

p= \frac{45}{11} = 4.09 g/cm^3

therefore, density of a material would be, 4.09 g/cm^3

and its units is g/cm^3

7 0
3 years ago
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