Answer:
Step-by-step explanation:
Perimeter of a rectangle = 2(L +W)
Given L = W + 2 and the perimeter is greater than 112 meters?
P rect < 2(L +W) L = W + 2
P rect < 2(W + 2 +W)
< 2(2W+2)
112 < 4W + 4 solve for W
(112 - 4)/4 < (4W +4 - 4)/4
108/4 < (4W + 0)/4
27 < W
the width has to be greater than 27 meters
Put the given information into the formula and solve for the variable of interest.
.. V = π*r^2*h
.. 24 = π*(h/3)^2*h
.. 24 = π/9*h^3
.. 9*24/π = h^3
.. ∛(216/π) = h
.. h = (6/π)√(π^2) ≈ 4.097 . . . . units
The height of the cylinder is about 4.097 units.
Answer:
I guess the sister picked 20 apples
Step-by-step explanation:
I have no explaination
P(both work) = ((10-3)/10)*((10-3-1)/9) = (7/10)*(6/9) = 42/90
<span>P(at least one does not work) = 1 - P(both work) = 1 - 42/90 = 48/90 = 24/45.</span>
