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3 years ago

-5x+9-2y+8(-2x-5)+8y+12-

Mathematics

1 answer:

MrMuchimi3 years ago

8 0

Answer:

-21x+6y-19

Step-by-step explanation:

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Find the mean, median, and interquartile for the data set below. Round your answer to the nearest tenth. 27,16,8,5,19,14,22,31,1

slavikrds [6]

Mean: 15.92
Median: 26
interquartile range: 14-16

3 0

3 years ago

Help me please I beg you

Dmitrij [34]

Answer:

Neither

Step-by-step explanation:

We need to transform one of the equations into its slope-intercept form:

y + 2/5x = 8

Subtract 2/5x from both sides:

y = -2/5x + 8

y = -5/2x - 7

Graphing both lines, they do intersect at point (-7.14, 10.86), but they are not parallel, nor are they perpendicular from each other. By definition, perpendicular lines must appear to be perpendicular (that is, they intersect at a 90° angle).

Looking at the attached graph (where the purple line is y = -2/5x + 8), their lines do not form a 90° angle.

Therefore, the correct answer is neither.

Please mark my answers as the Brainliest, if you find my explanations helpful :)

5 0

3 years ago

Read 2 more answers

3/4 3√128. simplify? kindly

lisov135 [29]

Answer: 3∛2

Step-by-step explanation:

First, factor 128 .... you need three common factors to bring one on the outside of the radical.

$\dfrac{3}{4}\sqrt[3]{128} \\\\\\=\dfrac{3}{4}\sqrt[3]{4\cdot 4\cdot 4\cdot 2} \\\\\\=\dfrac{3}{4}\cdot 4\sqrt[3]{2} \\\\\\=\large\boxed{3\sqrt[3]{2} }$

6 0

4 years ago

Read 2 more answers

I need the answer and the EQUATION for this problem, "It costs $13 for admission to an amusement park, plus $1.50 for each ride.

Allisa [31]

($35.50-$13) divided by $1.50=$22.5 divided by $1.50=15 rides

you can go on 15 rides.

4 0

3 years ago

Show that 3x^2 -2x + 1 is always greater than 0. ( This is an Additional Math Question )

Leviafan [203]

Answer:

3x^2 -2x + 1 =3(x^2-2/3x+1/3)=3(x-1/3)^2+2/9*3= 3(x-1/3)^2+2/3

(x-1/3)^2 is greater or equal to zero

3(x-1/3)^2 is greater or equal to zero

and 2/3 is greater than zero

So there sum is greater than zero

Proved

Step-by-step explanation:

3x^2 -2x + 1 =3(x^2-2/3x+1/3)

Consider x^2-2/3x+1/3

Remember that (a-b)^2 =a^2-2ab+b^2

x^2=a^2

a=x

-2/3x= -2*x*b

b=1/3

S0 (x-1/3)^2= x^2-2/3x+1/9

x^2-2/3x+1/3= x^2-2/3x+1/9+1/3-1/9= (x-1/3)^2+2/9

3x^2 -2x + 1 =3(x^2-2/3x+1/3)=3(x-1/3)^2+2/9*3= 3(x-1/3)^2+2/3

(x-1/3)^2 is greater or equal to zero

3(x-1/3)^2 is greater or equal to zero

and 2/3 is greater than zero

So there sum is greater than zero

Proved

6 0

3 years ago