We can write the equation in point-form in this case. The equation should be:
y-y1 = m(x-x1)
y and x can be any point in the line, so we leave them just like that in the equation, we don’t have to add any numbers to them. m is the slope of the line, and (x1, y1) is the given point in the line, which is (-1, 1) in this case.
Now, just substitute the number in,
y - 1 = -2 [x - (-1)]
y - 1 = -2 (x+1)
y - 1 = -2x - 2
2x + y + 1 = 0
So, 2x + y + 1 = 0 is your answer.
Answer:
50
Step-by-step explanation:
Answer:
Step-by-step explanation:
6cos^2(x) + 7cos(x) +2 = 0
Call cos(x) = y to change this to something a little bit more familiar.
6y^2 + 7y + 2 =0
This equation is a quadratic. Solve it first. Then we'll go back to solving for cos(x)
This equation factors into 2 possible answers
(3y + 2)(2y + 1) = 0
3y + 2 = 0
3y = - 2
y = - 2/3
2y + 1 = 0
2y = - 1
y = - 1/2
Now let's start with
cos(x) = - 1/2
That means that x is in quadrant two or three.
cos-1(1/2) = 60 degrees.
Quad 2: x = 180 - 60 = 120
Quad 3: x = 180 + 60 = 240
Now cos(x) = - 2/3
cos-1(2/3) = 48.19
Quad 2: x = 180 - 48.19 = 131.81
Quad 3: x = 180 + 48.19 = 228.19
Answer: 6
Step-by-step explanation: Look at the other triangle
Answer:
132cm²
Step-by-step explanation:
You can find the area of the entire shape by calculating the area of seperate smaller shapes.
You can split them up into 2 rectangles, one with a base of 7cm and height of 4cm, and another one with a base of 7cm and height of 8cm. You also have 2 triangles, with a base of 19cm - 7cm / 2 = 6cm since it is the entire bottom line subtracted by the top; they will have a height of 8cm each.
To calculate the rectangles areas, simply do length x width, which are:
4cm x 7cm = 28cm²
8cm x 7cm = 56cm²
Next, since the triangles are similar in measurements, instead of doing the normal calculation to find the area of a triangle, you can do base times height again, which is:
6cm x 8cm = 48cm²
Add all the answers together to get the final area, which is 132cm².
