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hjlf
3 years ago
10

I need help asap with math

Mathematics
1 answer:
Dmitrij [34]3 years ago
4 0
I'm not even going to bother with the substitution method.
Instead of all that, I just want to show you something:

Take the FIRST equation:

                                       y - 2x = 8
Add  2x  to
each side:                      y        = 8 + 2x

Multiply each
side by  2 :                    2y  =  16 + 4x

Look at that !  The first equation says the same thing as the second one !
Both of them are actually the same equation.
You actually have only one equation, with 'x' and 'y' in it.
If you graph it, the graph is a straight line, and EVERY point
on the line is a solution of the equation.

==>  There are an infinite number of solutions, because
they only gave you one equation, with two unknown variables.
To find a unique solution, you'd need two equations.
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Write the set of all real numbers greater than 19 and less than 32 in set-builder notation.
Aleks04 [339]

Answer: {xI x ∈ R, 19 < x < 32}

Step-by-step explanation:

This notation is:

{xI condition1, condition2, ...}

The first condition is:

From what set we take the values of x?

From the set of real numbers.

x ∈ R

The other conditions are the limitations that we have for x, in this case:

19 < x < 32

Then we can write this as:

{xI x ∈ R, 19 < x < 32}

8 0
2 years ago
8wsquared2<br><img src="https://tex.z-dn.net/?f=8w%20%7B2%20%7D%5E%7B2%7D%20%20-%2018w" id="TexFormula1" title="8w {2 }^{2} - 1
balandron [24]

{\text{Here, we have the algebraic expression}} \hfill \\ 8w \times {2^2} - 18w \hfill \\ {\text{For simplifying the expression, first we solve the exponent part,}} \hfill \\ {\text{and then the resultant will be multiply with the monomial }}18w \hfill \\ 8w \times {2^2} - 18w \hfill \\ = 8 \times w \times {2^2} - 18w \hfill \\= \left( {8 \times {2^2}} \right) \times w - 18w\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\left[ {\because \,{\text{By associative law }}a \times \left( {b \times c} \right) = \left( {a \times b} \right) \times c} \right] \hfill \\   = \left( {8 \times 4} \right) \times w - 18w \hfill \\   = 32 \times w - 18w \hfill \\= 32w - 18w \hfill \\= 14w \hfill \\

4 0
3 years ago
HELP PLS I HABE BEEN STARING AT THUS QUESTION FOR SO LONG​
kari74 [83]

Answer:

56%

Step-by-step explanation:

Reducing the picture by 80% and then by 70% gives a reduction of 56%

70% of 80 = 0.7 × 80 = 56%

7 0
3 years ago
Can you give me the answer? Ill give brainliest for the right answer
Serga [27]

Answer:

I believe the answer is b

Step-by-step explanation:

I might be wrong

3 0
2 years ago
Read 2 more answers
the area of a trapezoid is 780 cm squared. the shorter base is 48 cm and the height is 15 cm. Find the length of the other base
Anna35 [415]
If you multiply 48cm times 15cm,you get 720cm.Which would leave you with 60 left because 780 minus 720 equals 60.The height of the other base is 60cm.
6 0
3 years ago
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