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Pie
3 years ago
11

Please help me thank you​

Mathematics
1 answer:
Ket [755]3 years ago
7 0

Answer: D. 2x² + 3/2.x - 5

Step-by-step explanation:

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What I'd the equation of a line that passes through points (-2,6) and (4,-3)?
Blababa [14]

slope = (y2-y1)/(x2-x1)

 m = (-3-6)/(4--2)

  = -9/6

=-3/2

y -y1 = m(x-x1)

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y-6 =-3/2 (x+2)

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2 years ago
Find the equation of the line through point (-5,5) and perpendicular to y = 5/9x - 4
tankabanditka [31]

Answer:

9x+5y=-20

Step-by-step explanation:

y = \frac{5}{9} x - 4

compare with that y=mx+c

where m=slope .

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As the lines are perpendicular

m1*m2=\ -1

m2 \ =\ \frac{-1}{m1}

therefore m2=\frac{-9}{5}

Now from the equation

y - b = m(x - a ) this equation passing to the point (-5,5) with m=\frac{-9}{5}

y-5=\frac{-9}{5} (x+5)\\5y-25=-9x\ -45\\9x+5y=-20

Therefore equation is

9x+5y=-20

7 0
3 years ago
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