For this case we first write the equation of which we will use: I (db) = 10log (l / l) We substitute the value of l. We have then: l = 10 ^ 8lo Substituting in the given equation: I (db) = 10log ((10 ^ 8lo) / lo) Rewriting: I (db) = 10 * log (10 ^ 8) I (db) = 80 Answer: I (db) = 80 option 4
