A car is traveling at 55 mi/hour. What is the cars speed in feet per second

Mathematics

2 answers:

babymother [125]3 years ago

7 0

Answer:

about 81 feet per second.

Step-by-step explanation:

To convert MPH into feet per second you must first take your MPH (55 in this case) and multiply it by 5,280 and then divide the product of 55*5,280, thus giving you 80.666666 which is presumably rounded off to 81.

Shalnov [3]3 years ago

6 0

Answer:

Step-by-step explanation:

You need two conversion factors:

1 mile = 5280 ft, so (52780 ft)/(1 mile) = 1

1 hour = 3600 seconds, so (1 hour)/(3600 seconds) = 1

55 mi/hour * (5280 ft)/(1 mile) * (1 hour)/(3600 seconds) = 80.6666... ft/sec

Answer: 80.7 ft/sec

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Katena32 [7]

Let's move like a crab, backwards some.

after 2 years?

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$1000\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &2
\end{cases}
\\\\\\
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after 3 years?

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$1000\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &3
\end{cases}
\\\\\\
A=1000\left(1+\frac{0.03}{1}\right)^{1\cdot 3}\implies A=1000(1.03)^3$

is that enough to pay the $1100?

now, let's write 1000(1+r)² in standard form

1000( 1² + 2r + r²)

1000(1 + 2r + r²)

1000 + 2000r + 1000r²

1000r² + 2000r + 1000 <---- standard form.

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3 years ago

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zubka84 [21]

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3 years ago

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Degger [83]

Answer:

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Step-by-step explanation: