Answer:
![y = \dfrac{1}{3}x + 1](https://tex.z-dn.net/?f=%20y%20%3D%20%5Cdfrac%7B1%7D%7B3%7Dx%20%2B%201%20)
Step-by-step explanation:
The given line is in slope-intercept form,
y = mx + b,
where m is the slope.
The slope of the given line is 1/3, so m = 1/3.
Parallel lines have equal slopes, so the slope of the parallel line is also 1/3.
y = 1/3 x + b
Now we can find the equation of the parallel line through point (6, 3) by using the given point's coordinates for x and y and solving for b.
3 = (1/3)(6) + b
3 = 2 + b
b = 1
Equation: ![y = \dfrac{1}{3}x + 1](https://tex.z-dn.net/?f=%20y%20%3D%20%5Cdfrac%7B1%7D%7B3%7Dx%20%2B%201%20)
Answer:
Step-by-step explanation:
3/6 is 0.5
36/100 is 0.36
4/11 is 0.363636
9/25 is 0.36
Hope it helped :)
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Solution ~
or it can also be expressed as ~
The value of p that makes the given equation true is equal to: B. p = -5
<u>Given the following equation:</u>
To find a value of p that makes the given equation true:
In this exercise, you're required to determine a value of p that satisfies the given equation true such that when substituted into the equation, it has a true result or outcome.
Rearranging the equation by collecting like terms, we have:
![3p - 8 = -23\\\\3p=-23+8\\\\3p=-15\\\\p=\frac{-15}{3}](https://tex.z-dn.net/?f=3p%20-%208%20%3D%20-23%5C%5C%5C%5C3p%3D-23%2B8%5C%5C%5C%5C3p%3D-15%5C%5C%5C%5Cp%3D%5Cfrac%7B-15%7D%7B3%7D)
p = -5
Find more information: brainly.com/question/3600420
Answer:
About 5043.58
Step-by-step explanation:
The standard form for an exponential decay after t time is:
![\displaystyle f(t)=a(r)^{t/d}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f%28t%29%3Da%28r%29%5E%7Bt%2Fd%7D)
Where a is the initial value, r is the rate decay, t is the time that has passed, and d is the amount of time it takes for 1 cycle.
The initial value is 9800. So a = 9800.
The quantity cuts in half. So, r = 1/2.
And it cuts in half every 6 days. For this question, we will convert this to hours. 6 days = 144 hours. So, we can let d = 144, where t will be in hours.
Therefore, our function is:
![\displaystyle f(t)=9800\Big(\frac{1}{2}\Big)^{t/144}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f%28t%29%3D9800%5CBig%28%5Cfrac%7B1%7D%7B2%7D%5CBig%29%5E%7Bt%2F144%7D)
Where t is the amount of time that has passed, in hours.
Then the quantity left after 138 hours will be:
![\displaystyle f(138)=9800\Big(\frac{1}{2}\Big)^{138/144}\approx 5043.58](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f%28138%29%3D9800%5CBig%28%5Cfrac%7B1%7D%7B2%7D%5CBig%29%5E%7B138%2F144%7D%5Capprox%205043.58)