No of outcomes =16
favourable outcome=4
<span>probability of getting exactly 3 heads=0.25</span>
Answer:
0.0032
The complete question as seen in other website:
There are 111 students in a nutrition class. The instructor must choose two students at random Students in a Nutrition Class Nutrition majors Academic Year Freshmen non-Nutrition majors 17 18 Sophomores Juniors 13 Seniors 18 Copy Data. What is the probability that a senior Nutrition major and then a junior Nutrition major are chosen at random? Express your answer as a fraction or a decimal number rounded to four decimal places.
Step-by-step explanation:
Total number of in a nutrition class = 111 students
To determine the probability that the two students chosen at random is a junior non-Nutrition major and then a sophomore Nutrition major, we would find the probability of each of them.
Let the probability of choosing a junior non-Nutrition major = Pr (j non-N)
Pr (j non-N) = (number of junior non-Nutrition major)/(total number students in nutrition class)
There are 13 number of junior non-Nutrition major
Pr (j non-N) = 13/111
Let the probability of choosing a sophomore Nutrition major = Pr (S N-major)
Pr (S N-major)= (number of sophomore Nutrition major)/(total number students in nutrition class)
There are 3 number of sophomore Nutrition major
Pr (S N-major) = 3/111
The probability that the two students chosen at random is a junior non-Nutrition major and then a sophomore Nutrition major = 13/111 × 3/111
= 39/12321
= 0.0032
Answer:
Step-by-step explanation:
red = 25
green = 25 + 35 = 60
yellow = 15
red = 25/5 = 5
green = 60/5 = 12
yellow = 15/5 = 3
Red + green = 5 + 12 = 17 boxes
yellow = 3 boxes
17 - 3 = 14 boxes
There are 14 more boxes of red and green cars than yellow cars.
Answer:
See below.
Step-by-step explanation:
First, we can see that
.
Thus, for the question, we can just plug -1 in:

Saying undefined (or unbounded) will be correct.
However, note that as x approaches 2, the values of y decrease in order to get to -1. In other words,
will always be greater or equal to -1 (you can also see this from the graph). This means that as x approaches 2, f(x) will approach -.99 then -.999 then -.9999 until it reaches -1 and then go back up. What is important is that because of this, we can determine that:

This is because for the denominator, the +1 will always be greater than the f(x). This makes this increase towards positive infinity. Note that limits want the values of the function as it approaches it, not at it.
Answer:
(0, 1)
Step-by-step explanation:
6^0 = 1
For exponential function, always > 0, never = 0