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Lana71 [14]
3 years ago
11

Does anyone know how to do this??

Chemistry
1 answer:
mihalych1998 [28]3 years ago
4 0
How to do what? There's no problem here. If you send a picture I can do my best to help you
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The gas in an engine cylinder is compressed until it has a volume of 0.045 liter and an absolute pressure of 28 atmospheres. If
Sonbull [250]

The  temperature  in K  is  767.4 K

<u><em>  calculation</em></u>

This is calculated using the ideal gas equation

that is PV =nRT

where;

P(pressure)= 28 atm

V(volume) = 0.045 L

n(number of moles)= 0.020 moles

R( gas  constant)  =0.0821 L.atm/mol.K

T(temperature)= ? K\


make T the subject of   the formula  by diving  both side of equation by nR

T =PV/nR

T ={ (28 atm x 0.045 L) /( 0.020 mol x 0.0821 L.atm/mol.K)}  =767.4 K



7 0
4 years ago
Read 2 more answers
3. compared to the melting points of ionic compounds, the melting points of molecular solids tend to be ___.
Reil [10]
C) Lower, 

They're lower because molecular solids form IMF's such as Dipole-Dipole and H-Bonds, while Ionic bonds are much more powerful.
3 0
3 years ago
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Explain how to produce a longitudinal wave on a spring that has large energy. There are two answers; one involves wavelength and
melamori03 [73]
Compressions are regions of high pressure due to particles being close together
rarefactions are regions of low pressure due to particles being spread further apart
Longitudinal waves are often demonstrated by pushing and pulling a stretched slinky spring
4 0
3 years ago
How many atoms are in 57.5 liters of xenon gas at STP
TiliK225 [7]

Answer:

1.55 × 10²⁴ atoms Xe

General Formulas and Concepts:

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Moles
  • STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

[Given] 57.5 L Xe at STP

[Solve] atoms Xe

<u>Step 2: Identify Conversions</u>

[STP] 22.4 L = 1 mol

Avogadro's Number

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                       \displaystyle 57.5 \ L \ Xe(\frac{1 \ mol \ Xe}{22.4 \ L \ Xe})(\frac{6.022 \cdot 10^{23} \ atoms \ Xe}{1 \ mol \ Xe})
  2. [DA] Divide/Multiply [Cancel out units]:                                                           \displaystyle 1.54583 \cdot 10^{24} \ atoms \ Xe

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

1.54583 × 10²⁴ atoms Xe ≈ 1.55 × 10²⁴ atoms Xe

4 0
3 years ago
1. Which of the following chemical reactions is an oxidation-reduction reaction?
dsp73

1) Answer is: WO3 + 3H2 → W + 3H2O.

Reduction reaction: W⁺⁶ + 6e⁻ → W⁰.

Oxidation reaction: H₂ → 2H⁺¹ + 2e⁻ / ×3; 3H₂ → 6H⁺¹ + 6e⁻.

Wolfram change oxidation number from +6 to 0 (reduction) and hydrogen change oxidation number from 0 to 01 (oxidation).

In other examples, elements do not change their oxidation numbers.

2) Answer is: It increases the average kinetic energy and there are more collision per minute.

The collision theory states that a certain fraction of the collisions (successful collisions) cause significant chemical change.

The successful collisions must have enough energy (activation energy).

Chemical bonds are broken and new bonds are formed.

Particles are in constant, random motion and possess kinetic energy, molecules faster and have more collisions.

8 0
3 years ago
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