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vfiekz [6]
4 years ago
11

The gas in an engine cylinder is compressed until it has a volume of 0.045 liter and an absolute pressure of 28 atmospheres. If

the engine cylinder contains 0.020 mole of gas, what is its temperature? The temperature of the gas is how many K.
Chemistry
2 answers:
Sonbull [250]4 years ago
7 0

The  temperature  in K  is  767.4 K

<u><em>  calculation</em></u>

This is calculated using the ideal gas equation

that is PV =nRT

where;

P(pressure)= 28 atm

V(volume) = 0.045 L

n(number of moles)= 0.020 moles

R( gas  constant)  =0.0821 L.atm/mol.K

T(temperature)= ? K\


make T the subject of   the formula  by diving  both side of equation by nR

T =PV/nR

T ={ (28 atm x 0.045 L) /( 0.020 mol x 0.0821 L.atm/mol.K)}  =767.4 K



Aleksandr-060686 [28]4 years ago
6 0

somebody answer i need it for my class

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