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lorasvet [3.4K]
4 years ago
14

35.7 x 10^-2 proper scientific notation

Mathematics
1 answer:
seropon [69]4 years ago
6 0

Answer:0.357 meters is the answer hope this help give me a brainest please

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SOMEBODY, ANY BODY, HELP ME WITH THIS PROBLEM PLS!!!!!
Crazy boy [7]
Because I wanna say sorry if I'm wrong

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3 years ago
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Two years ago, Rob bought some shares of a stock, and today those shares have a value of $19.80 each. The price when Rob bought
navik [9.2K]

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$14.85 per share

Step-by-step explanation:

(3/4) of the current price = (3/4)·($19.80) = $14.85

Rob paid $14.85 per share.

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4 years ago
Hey can you please help me posted picture of question
Debora [2.8K]
We can use quadratic formula to determine the roots of the given quadratic equation.

The quadratic formula is:

x= \frac{-b+- \sqrt{ b^{2} -4ac} }{2a}

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a = coefficient of squared term = 2
c = constant term = 15

Using the values, we get:
x= \frac{11+- \sqrt{121-4(2)(15)} }{2(2)} \\  \\ 
x= \frac{11+-1}{4} \\  \\ 
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So, the correct answer to this question are option B and D
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4 years ago
Match each expression on its left to its product
maw [93]

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Step-by-step explanation:

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5 0
3 years ago
Given the point and slope, write the equation of the line
Ratling [72]

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\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{-1}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-1-4}{6-1}\implies \cfrac{-5}{5}\implies -1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-4=-1(x-1) \\\\\\ y-4=-x+1\implies y=-x+5


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\bf (\stackrel{x_1}{-12}~,~\stackrel{y_1}{14})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{-1}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-1-14}{6-(-12)}\implies \cfrac{-15}{6+12}\implies \cfrac{-15}{18}\implies -\cfrac{5}{6}


\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-14=-\cfrac{5}{6}[x-(-12)] \\\\\\ y-14=-\cfrac{5}{6}(x+12)\implies y-14=-\cfrac{5}{6}x-10\implies y=-\cfrac{5}{6}x+4

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3 years ago
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