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katen-ka-za [31]
3 years ago
11

X/15+1/5<2/5 solve for x. Show all work.

Mathematics
2 answers:
Nitella [24]3 years ago
5 0
X=3 is the answer I think
Len [333]3 years ago
4 0
Subtract 1/5 on both sides.

x/15<1/5

To make x on its own, we will then multiply 15 on both sides.

15/1 multiplied by 1/5 is 15/5

15/5 simplifies to 3.

x/15 multiplied by 15 is x.

x < 3
 
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El numeral 32012(4) representado en el sistema decimal, porfavor
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<h2>1)</h2>

(x - 4) {}^{2}  - 28 = 8 \\ (x - 4) {}^{2}  = 8 + 28 \\ (x - 4) {}^{2}  = 36

This must be true for some value of x, since we have a quantity squared yielding a positive number, and since the equation is of second degree,there must exist 2 real roots.

\sqrt{(x - 4) {}^{2} }  =  ± \sqrt{36}  \\x - 4 = ±6 \\ x _{1}- 4 = 6 \:  \:  \:  \:  \:  \:  \: \:  \:  \:  x _{2}- 4 =  - 6 \\ x_{1} = 6 + 4 \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x_{2} =  - 6 + 4 \\ x_{1} = 10 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \: \:  \: x_{2} =  - 2

<h2>2)</h2>

Well he started off correct to the point of completing the square.

(x - 3)  {}^{2}  = 16 \\ x - 3 = ±4 \\  \: x_{1}  - 3 = 4 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x_{2}  - 3 =  - 4 \\ x_{1}  = 7 \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x_{2}  =  - 1

8 0
1 year ago
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