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Juli2301 [7.4K]
3 years ago
5

On a coordinate plane, a line goes through (negative 3, 2) and (0, 1). A point is at (3, 4). What is the equation of the line th

at is perpendicular to the given line and passes through the point (3, 4)? y = –One-thirdx + 5 y = –One-thirdx + 3 y = 3x + 2 y = 3x − 5
Mathematics
2 answers:
Citrus2011 [14]3 years ago
8 0

Answer:

The Answer is 1

Step-by-step explanation:

Its so eazy

Novay_Z [31]3 years ago
6 0

Answer:

y=3x-5

Step-by-step explanation:

step 1

Find the slope of the given line

we have

(-3,2) and (0,1)

The slope m is

m=(1-2)/(0+3)=-1/3

step 2

Find the slope of the line perpendicular to the given line

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of its slopes is -1)

so

The slope is

m=3

step 3

Find the equation of the line in point slope form

we have

m=3

point(3,4)

y-4=3(x-3) ----> equation in point slope form

Convert to slope intercept form

y=3x-9+4

y=3x-5

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\bf \qquad \textit{Amount for Exponential Decay}
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3 years ago
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Likurg_2 [28]

Answer:

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Step-by-step explanation:

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Klio2033 [76]
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