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Digiron [165]
3 years ago
5

Solve −2x2 − 16x − 44 = 0.

Mathematics
2 answers:
Mashutka [201]3 years ago
5 0

<u>Answer</u>

x = -4 plus or minus "i" times the square root of 6


<u>Explanation</u>

 −2x² − 16x − 44 = 0.

 −2x² − 16x = 44

Dividing by -2

x² + 8x = -22

x² + 8x + 4² = -22 + 4²

(x + 4)² = -22 + 16

(x + 4) ² = -6

(x + 4) = √-6

Remember √(-1) = i

(x + 4) = i√6                    or  (x + 4) = -i√6

x = -4 + i√6                          x = -4 - i√6                      



Mazyrski [523]3 years ago
3 0
I hope this helps you

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12(3w+8)=25 what is the w
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7 0
3 years ago
Find the surface area of the two following figures. Show all your work.
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7 0
2 years ago
A parabola has a focus of F(2, -0.5) and a directrix of y=-1.5 P(x,y) represents any point on the parabola, while D(x, -1.5) rep
prohojiy [21]
The sketch of the parabola is attached below

We have the focus (a,b) = (2, -0.5)
The point P(x,y)
The directrix, c at y=-1.5

The steps to find the equation of the parabola are as follows

Step 1
Find the distance between the focus and the point P using Pythagoras. We have two coordinates; (2, -0.5) and (x,y).
We need the vertical and horizontal distances to find the hypotenuse (the diagram is shown in the second diagram).
The distance between the focus and point P is given by
\sqrt{ (x-a)^{2}+ (y-b)^{2} }

Step 2
Find the distance between the point P to the directrix c. It is a vertical distance between y and c, expressed as y-c

Step 3
The equation of parabola is then given as 
\sqrt{ (x-a)^{2}+ (y-b)^{2} }=y-c
(x-a)^{2}+ (y-b)^{2}= (y-c)^{2} ⇒ substituting a, b and c
(x-2)^{2}+ (y--0.5)^{2}  = (y--1.5)^{2}
(x-2)^{2}+ (y+0.5)^{2}= (y+1.5)^{2}⇒Rearranging and making y the subject gives

y= \frac{ x^{2} }{2} -2x+1

7 0
3 years ago
Please answer this correctly
Firdavs [7]

Answer:

Simple:

 (-2.5,-1) goes 2.5 units left and 1 units down

 (0.5,2) goes half a unit right and 2 units up

Step-by-step explanation:

5 0
3 years ago
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