If the line on a distance-versus-time graph and the line on a speed-versus-time graph are both straight lines going through the
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This question can be solved by using the equations of motion.
a) The initial speed of the arrow is was "9.81 m/s".
b) It took the arrow "1.13 s" to reach a height of 17.5 m.
a)
We will use the second equation of motion to find out the initial speed of the arrow.
where,
vi = initial speed = ?
h = height = 35 m
t = time interval = 2 s
g = acceleration due to gravity = 9.81 m/s²
Therefore,
<u>vi = 9.81 m/s</u>
b)
To find the time taken by the arrow to reach 17.5 m, we will use the second equation of motion again.
where,
g = acceleration due to gravity = 9.81 m/s²
h = height = 17.5 m
vi = initial speed = 9.81 m/s
t = time = ?
Therefore,
solving this quadratic equation using the quadratic formula, we get:
t = -3.13 s (OR) t = 1.13 s
Since time can not have a negative value.
Therefore,
<u>t = 1.13 s</u>
Learn more about equations of motion here:
brainly.com/question/20594939?referrer=searchResults
The attached picture shows the equations of motion in the horizontal and vertical directions.
George's speed per second is 76.92 m/s
George's velocity in meters per second was 38.46 m/s (North)
<u>Explanation:</u>
When dividing the total distance covered by object by time, we get the value for average speed.
<u>Given:</u>
t = 13 seconds
Calculate the distance without consideration of motion’s direction. So, the distance walks 750 m north first, and then turn around walks 250 m south, so the total distance covered is
d = 750 + 250 = 1000 meters
To find the rate per second, simply divide the distance by the time.
In given case, the students walks 750 m north first, and then turn around walk 250 m south. The displacement is the distance in a straight line between the initial and final position: therefore, in this case, the displacement is
d = 750 (north) - 250 (south) = 500 m (north)
The time taken is t = 13 s
So, the average velocity is (North)
And the direction is north (the same as the displacement).