1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Shalnov [3]
3 years ago
10

A 90N force towards postive x-axis, A 50N force towards negative x-axis applied on 5kg object. Find:- A) the net force on the ob

ject and B) the acceleration of the object​
Physics
1 answer:
Ne4ueva [31]3 years ago
5 0

Answer:

a. Net force = 40 Newton.

b. Acceleration = 8m/s²

Explanation:

Given the following data;

Force on postive x-axis = 90N

Force on negative x-axis = 50N

Mass = 5kg

a. To find the net force;

Net force can be defined as the vector sum of all the forces acting on a body or an object i.e the sum of all forces acting simultaneously on a body or an object.

The net force is equal to the difference between the two forces applied because they are acting in opposite directions.

Net force = 90 - 50

Net force = 40N

b. To find the acceleration;

Acceleration = net force/mass

Acceleration = 40/5

Acceleration = 8m/s²

You might be interested in
A) A real object 4.0 cm high stands 30.0 cm in front of a converging lens of focal length 23 cm. Find the image distance, the im
vfiekz [6]

Explanation:

Given that,

Height of object = 4.0 cm

Distance of the object u= -30.0 cm

Focal length = 23 cm

We need to calculate the image distance

Using lens's formula

\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}

Where, u = object distance

v = image distance

f = focal length

Put the value into the formula

\dfrac{1}{v}-\dfrac{1}{-30}=\dfrac{1}{23}

\dfrac{1}{v}=\dfrac{1}{23}-\dfrac{1}{30}

\dfrac{1}{v}=\dfrac{7}{690}

v=98.57\ cm

We need to calculate the height of the image

Using formula of height

\dfrac{h'}{h}=\dfrac{-v}{u}

Where, h' = height of image

h = height of object

\dfrac{h'}{4}=\dfrac{-98.57}{-30}

h'=\dfrac{98.57\times4}{30}

h'=13.14\ cm

The image is real and inverted.

(b). Now, object distance u = 13.0 cm

We need to calculate the image distance

Using lens's formula

\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}

Put the value into the formula

\dfrac{1}{v}=\dfrac{1}{23}-\dfrac{1}{13.0}

\dfrac{1}{v}=-\dfrac{10}{299}

v=-29.9\ cm

We need to calculate the height of the image

\dfrac{h'}{4}=\dfrac{-(-29.9)}{-13.0}

h=-\dfrac{29.9\times4}{13.0}

h=-9.2\ cm

The image is virtual and erect.

Hence, This is required solution.

6 0
3 years ago
If the force causing a mass to accelerate is multiplied by a number while keeping the mass the same, what happens to the acceler
klasskru [66]

Answer: If mass remains constant and you double the force you will double the acceleration.

3 0
3 years ago
A steam engine absorbs 1.98 × 105 j and expels 1.49 × 105 j in each cycle. assume that all of the remaining energy is used to do
VikaD [51]
B) The heat absorbed by the engine is Q_{in} = 1.98 \cdot 10^5 J while the heat expelled is Q_{out} = 1.49 \cdot 10^5 J, therefore the work done by the engine is the difference between the heat absorbed and the heat expelled:
W=Q_{in} - Q_{out} = 1.98 \cdot 10^5 J - 1.49 \cdot 10^5 J = 0.49 \cdot 10^5 J

a) The efficiency of the engine is the ratio between the work done by the engine and the heat absorbed, therefore:
\eta= \frac{W}{Q_{in}} = \frac{0.49 \cdot 10^5 J}{1.98 \cdot 10^5 J}=0.247 = 24.7\%
8 0
4 years ago
Consider the average speed of a runner who jogs around a track four times. The distance (400m) remains constant for each lap. Ho
Yuki888 [10]

D) decreases, inverse

Explanation:

The average speed of each lap decreases. This is an example of an inverse relationship.

Speed is the rate of change of distance with time. In calculating the average speed, we should understand that the total length of path is taken into consideration and so is the total time taken.

  Average speed = \frac{total distance}{total time}

It was explained that after every 5 seconds the speed of the runner becomes slower.

There is definitely an inverse relationship between average speed and the total time taken.

An inverse relationship is such that as one variable increases, the other diminishes.

As average speed reduces the time taken increases.

learn more:

Speed brainly.com/question/1386181

#learnwithBrainly

7 0
3 years ago
How long would it take an object to stop if it is moving at 15m/s and has an acceleration -0.5m/s^2? Please show your work.
elena-14-01-66 [18.8K]

Time = 15/-0.5 = 14.5/-0.5 = 14.5s

The answer is 14.5s

Sorry no one would answer it sooner.

3 0
3 years ago
Other questions:
  • The rate at which light energy is radiated from a source is measured in which of the following units?
    9·1 answer
  • Which microscope is the most powerful and can map the atoms on the surface of an object?
    14·2 answers
  • What are the two reasons why metals are good conductors of electricity?​
    15·2 answers
  • What net force is required to push a sofa with a mass of 59 kilograms so that it accelerates at 9.75 meters/secondÆ? (Assume a f
    7·1 answer
  • During summer break, Jamie's family went camping in the mountains. There were no roads to their camp, 8 miles away, and it took
    5·2 answers
  • A proton in a particular electric field experiences an electric force whose magnitude is equal to the weight of the proton. Dete
    8·1 answer
  • Henry can lift a 200 N load 20 m up a ladder in 40 s. Ricardo can lift twice the load up one-half the distance in the same amoun
    7·2 answers
  • Mr. Voytko wants to know how high in meters he can lift an 0.3 kg apple with 7.35 joules?
    12·1 answer
  • Can we build up an electric circuit without source of electric current
    7·2 answers
  • Describe how sound at a concert is different from the front row and the back.
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!