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timama [110]
3 years ago
5

Apply Newton's first law of motion to a sprinter in a race.

Physics
1 answer:
sergejj [24]3 years ago
8 0
First law of motion is applied in speranter of a car just like that if the car is moving alway's at sprint than if there is no any resistance than a car is moving such a speed which the car is  in that instant will be moving on the same speed forever.

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Please help me with this question
snow_lady [41]

politics. Famous possible eg is of Werner Heisenberg in WW2. He delayed German attempt to build a nuclear bomb. US did build one ... hiroshima and nagasaki.

debbie may have got skilfully lucky by trial and error

6 0
3 years ago
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When making sweet tea, McDonalds adds the sugar while the tea is hot. The sugar is added at this step so that the tea can be as
Lilit [14]

Answer:

d

Explanation:

we need the tea to be at first moist in order to get much more flavor. then supersaturated so that it increases the concentration of the flavor by it not being too sweet nor too salty. so just right.

3 0
3 years ago
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The continuous submarine mountain range which winds through all the oceans is called the mid-ocean
Artist 52 [7]
The continuous submarine mountain range which winds through all the oceans is called the mid-ocean <u>ridge.
</u>It is a form of a mountain which is found underwater, and it appeared there due to the movements of tectonic plates. It is responsible for the creation of new seafloor, meaning that the ground underwater changes constantly with the formation of these ridges. <u>
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5 0
3 years ago
The instantaneous speed of a particle moving along one straight line is v(t) = ate−6t, where the speed v is measured in meters p
beks73 [17]

Answer:

v_max = (1/6)e^-1 a

Explanation:

You have the following equation for the instantaneous speed of a particle:

v(t)=ate^{-6t}   (1)

To find the expression for the maximum speed in terms of the acceleration "a", you first derivative v(t) respect to time t:

\frac{dv(t)}{dt}=\frac{d}{dt}[ate^{-6t}]=a[(1)e^{-6t}+t(e^{-6t}(-6))]  (2)

where you have use the derivative of a product.

Next, you equal the expression (2) to zero in order to calculate t:

a[(1)e^{-6t}-6te^{-6t}]=0\\\\1-6t=0\\\\t=\frac{1}{6}

For t = 1/6 you obtain the maximum speed.

Then, you replace that value of t in the expression (1):

v_{max}=a(\frac{1}{6})e^{-6(\frac{1}{6})}=\frac{e^{-1}}{6}a

hence, the maximum speed is v_max = ((1/6)e^-1)a

5 0
3 years ago
Two examples of a stopping motion
Anton [14]
Pause?Freeze?
Stop?
Halt?
5 0
3 years ago
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