In a thundercloud there may be an electric
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Answer:
a. The acceleration of the hockey puck is -0.125 m/s².
b. The kinetic frictional force needed is 0.0625 N
c. The coefficient of friction between the ice and puck, is approximately 0.012755
d. The acceleration is -0.125 m/s²
The frictional force is 0.125 N
The coefficient of friction is approximately 0.012755
Explanation:
a. The given parameters are;
The mass of the hockey puck, m = 0.5 kg
The starting velocity of the hockey puck, u = 5 m/s
The distance the puck slides and slows for, s = 100 meters
The acceleration of the hockey as it slides and slows and stops, a = Constant acceleration
The velocity of the hockey puck after motion, v = 0 m/s
The acceleration of the hockey puck is obtained from the kinematic equation of motion as follows;
v² = u² + 2·a·s
Therefore, by substituting the known values, we have;
0² = 5² + 2 × a × 100
-(5²) = 2 × a × 100
-25 = 200·a
a = -25/200 = -0.125
The constant acceleration of the hockey puck, a = -0.125 m/s².
b. The kinetic frictional force, , required is given by the formula, F = m × a,
From which we have;
= 0.5 × 0.125 = 0.0625 N
The kinetic frictional force required, = 0.0625 N
c. The coefficient of friction between the ice and puck, , is given from the equation for the kinetic friction force as follows;
The coefficient of friction between the ice and puck, ≈ 0.012755
d. When the mass of the hockey puck is 1 kg, we have;
Given that the coefficient of friction is constant, we have;
The frictional force
The acceleration, a = /m = 0.125/1 = 0.125 m/s², therefore, the magnitude of the acceleration remains the same and given that the hockey puck slows, the acceleration is -0.125 m/s² as in part a
The frictional force as calculated here,
The coefficient of friction ≈ 0.012755 is constant
After 4 seconds the velocity function attains a=8.75m/s².
Given-
Velocity= 35m/s
time=4sec
To find out acceleration, we can understand the following-
Acceleration means rate of change of velocity.
In this question the velocity depreciates to zero i.e. the slope of the graph falls off with negative slope.
This value has negative impact on force as the resultant force is outcome of application of brakes where V=0 as time progresses.
Mathematically,
v- means velocity .
calculations-
a=35/4
a=8.75m/s²
To find out about acceleration -
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