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3 years ago

Which ordered pair is a solution of the equation? y+1=3(x – 4)

Mathematics

1 answer:

nignag [31]3 years ago

5 0

Answer:

Step-by-step explanation:

It is what it is

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<img src="https://tex.z-dn.net/?f=%5Cfrac%7Ba%5E%7B3%7Db%5E%7B5%7D%7D%7Ba%5E%7B4%7Db%7D" id="TexFormula1" title="\frac{a^{3}b^{5

aliina [53]

Answer:

b^4 / a

Step-by-step explanation:

I have attached the explanation above. hopefully this will help

3 0

3 years ago

Write an expression that gives the requested sum. the sum of the first 18 terms of the geometric sequence with first term 3 and

alina1380 [7]

I got 786432 when I use a(r^n-1)/(r-1)

8 0

3 years ago

A sample of blood pressure measurements is taken from a data set and those values (mm Hg) are listed below. The values are matc

swat32

Answer:

Step-by-step explanation:

Systolic. Calculate the mean

118+128+158+96+156+122+116+136+126+120+

=1276÷10 = 127.6.

To calculate the median arrange the values from the lowest to the highest.

96,116,118,120,122,126,128,136,156,158.

122+126+2=124.

Disastolic

80+76+74+52+90+88+58+64+72+82= 736÷10=73.6

To calculate the median arrange the values from the lowest to the highest.

52,58,64,72,74,76,80,82,88,90

Median= 74+76=150÷2=75.

Comparison

The Systolic and diastolic blood pressure measures different things, so comparing them is of no use.

It will be good if the relationship between the blood pressure can be investigated because the data are in pairs.

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=2x%5E2%2B5x%2B3%3D0" id="TexFormula1" title="2x^2+5x+3=0" alt="2x^2+5x+3=0" align="absmiddle"

melamori03 [73]

Answer:

$x=-\frac{3}{2},-1$

Step-by-step explanation:

$2x^2+5x+3=0$

Split the second term (5x) into two terms. Multiply the coefficient of the first term (2) by the constant term (3):

$2*3=6$

Find which two numbers add up to 5 and multiply into 6:

$3+2=5\\3*2=6\\3,2$

Split 5x as the sum of 3x and 2x:

$2x^2+3x+2x+3$

Now factor out a common term for the first 2 terms:

$2x^2+3x\\x(2x+3)$

And do the same for the last 2 terms:

$2x+3\\1(2x+3)$

Re-insert:

$x(2x+3)+1(2x+3)=0$

Factor out the common term 2x+3 and insert the values in front of the parentheses (x and 1):

$(2x+3)(x+1)=0$

Separate the parentheses and equal them to 0. Solve for x:

$2x+3=0\\2x+3-3=0-3\\2x=-3\\\\\frac{2x}{2}=\frac{-3}{2}\\\\ x=-\frac{3}{2}$

and

$x+1=0\\x+1-1=0-1\\x=-1$

5 0

3 years ago

Context inequality systems on

MariettaO [177]

Yea I don’t know it’s b

8 0

3 years ago

Read 2 more answers