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nydimaria [60]
3 years ago
9

(8–9a)a=−40+(6–3a)(6+3a)

Mathematics
2 answers:
elena-14-01-66 [18.8K]3 years ago
8 0

Answer:

a=-0.5

Step-by-step explanation:

Distributive property for left side, difference of squares for right side.

8a-9a^2=-40+36-9a^2

-9a^2 cancels out

8a=-4

a=-0.5

hjlf3 years ago
5 0

Answer: a= -\frac{1}{2} or in decimal form a = - 0.5

* Hopefully this helps:) Mark me the brainliest:)!! I Didn't provide work since you said work is not require.

∞ 234483279c20∞

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5 0
3 years ago
a circle has a center (3,5) and a diameter AB. The coordinates of A are (-4,6). what are the coordinates of B?
Kruka [31]
Find the length of the radius.

r= \sqrt{(3-(-4))^2+(5-6)^2}
\\r =  \sqrt{7^2+(-1)^2}
\\r= \sqrt{50} 
\\  r=5 \sqrt{2}

Find the length of the diameter.

d = 2r = 2 × 5√2 = 10√2

Point B must lie on a line AC, where C is a center of a circle.
Find equation of line AC.
A(–4, 6), C(3, 5)

y-y_1= \frac{y_2-y_1}{x_2-x_1}(x-x_1)
\\y-6= \frac{5-6}{3-(-4)}  (x-(-4))
\\y-6=- \frac{1}{7} (x+4)
\\7y-42=-x-4
\\x+7y-38=0 

The distance from B(x, y) to C(3, 5) is 5√2.
\sqrt{(x-3)^2+(y-5)^2}=5 \sqrt{2} 
 \\(x-3)^2+(y-5)^2=(5 \sqrt{2})^2 
\\(x-3)^2+(y-5)^2=50

Solve system of equations.
x+7y-38=0
\\(x-3)^2+(y-5)^2=50
\\
\\x=38-7y
\\(38-7y-3)^2+(y-5)^2=50
\\(35-7y)^2+(y-5)^2=50
\\1225-490y+49y^2+y^2-10y+25-50=0
\\50y^2-500y+1200=0
\\y^2-10y+24=0
\\y^2-6y-4y+24=0
\\y(y-6)-4(y-6)=0 \\(y-6)(y-4)=0 \\y_1=6,y_2=4


x_1=38-7y_1=38-7 \times 6 = 38-42=-4
\\x_2=38-7y_2=38-7 \times 4 = 38-28=10


Point B could have coordinates
\\
\\(x_1,y_1)=(-4,6),(x_2,y_2)=(10,4)


But (–4, 6) are the coordinates of point A.
Therefore, point B has coordinates (10,4).
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3 years ago
Hi could someone give me an answer? please?
umka21 [38]
A)= 2/20 or 1/10
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