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3 years ago

5

There were 36 cookies in a package. Chase invited 6 friends to his birthday party. How many cookies will each person get if all

the people get the same amount including chase.

1 answer:

podryga [215]3 years ago

4 0

7 cookies each without surpassing 36.

You might be interested in

Bill is 2 years older than his brother Will. If the product of their ages is one less than five times the sum of their ages, how

Advocard [28]

Answer:

Will's age = 9 years

Bill's age = 11years

Step-by-step explanation:

Let will age = x

Bill = x +2 since he is 2 years older

x(x+2) = 5( x +x+2) - 1

Opening brackets

x² + 2x = 5(2x + 2) - 1

x² + 2x = 10x + 10 - 1

x² + 2x = 10x + 9

Collect like terms

x² + 2x - 10x - 9 = 0

x² - 8x - 9 = 0

Solve quadratically using factorisation method by finding two factors of +9 that can add up to give -8, the coefficient of x.

The factors are -9 and +1

x² + x - 9x - 9 = 0

x(x + 1) -9( x +1)

x+1) (x -9) =0

x + 1 = 0 or x -9 =0

x = -1 or 9

Age can not be negative

Therefore,

Will's age = 9 years

Bill's age = x+2 = 9+2 = 11years

I hope this was helpful, please rate as brainliest

6 0

3 years ago

I am confused about how to do this problem and I don't think it should be hard, but I just don't know how to approach it, so if

solniwko [45]

Answer:

a) (0.555, 0) and (6, 0)

b) r = -3 and r = 1.8

c) (0.875, 0.676)

d) (0, 1.235)

Step-by-step explanation:

Set each term in the numerator and denominator equal to 0 and find r.

In the numerator:

r = 7/8, 5/9, or 6

In the denominator:

r = 9/5, 7/8, or -3

Zeros in the numerator that aren't in the denominator are r-intercepts.

Zeros in the denominator that aren't in the numerator are vertical asymptotes.

Zeros in both the numerator and the denominator are holes.

a) (0.555, 0) and (6, 0)

b) r = -3 and r = 1.8

c) Evaluate m(r) at r = 7/8. To do that, first divide out the common term (-8r + 7) from the numerator and denominator.

m(r) = (-9r+5)² (r−6)² / ( (-5r+9)² (r+3)² )

m(⅞) = (-9×⅞+5)² (⅞−6)² / ( (-5×⅞+9)² (⅞+3)² )

m(⅞) = (-23/8)² (-41/8)² / ( (37/8)² (31/8)² )

m(⅞) = (-23)² (-41)² / ( (37)² (31)² )

m(⅞) = 0.676

The hole is at (0.875, 0.676).

d) Evaluate m(r) at r = 0.

m(0) = (-9×0+5)² (0−6)² / ( (-5×0+9)² (0+3)² )

m(0) = (5)² (-6)² / ( (9)² (3)² )

m(0) = 1.235

The m(r)-intercept is (0, 1.235).

5 0

3 years ago

The Tetrahedron Superyacht designed by Jonathan Schwinge is a regular tetrahedron with edges 20 m long. The distance r from one

shusha [124]

A tetrahedron is a triangular pyramid. It has four triangular faces and four vertices.

In the question, we are told that the length of the edges are all equal = 20m and the length from one corner to the center of the base = 11.5m

We sketch a diagram of a tetrahedron with the given measurement as shown below

To find the height, we will use the Pythagoras theorem

20² = h² + 11.5²
h² = 20² - 11.5²
h² = 267.75
h = √267.75
h = 16.36 (rounded to two decimal places)

8 0

3 years ago

Read 2 more answers

Help me plz plz plz

Elan Coil [88]

The answer would be a

8 0

3 years ago

Read 2 more answers

Helpp ill mark u as brain list

kirill [66]

Answer:

16.C

17.20

Step-by-step explanation:

16.Add 8+5=13

17.Add 12+8=20

7 0

2 years ago