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jasenka [17]
3 years ago
11

A restaurant has two different seating options: a table and a family booth. A table can seat 2 people, and a family booth can se

at 6 people. The restaurant has a maximum capacity of 120 people. If the restaurant has 15 family booths, which inequality could be used to find t, the number of tables in the restaurant
Mathematics
1 answer:
Drupady [299]3 years ago
3 0

Answer:

t ≤ 15

Step-by-step explanation:

Let t = tables

6 * 15 + 2* t ≤ 120

90 + 2t ≤ 120

2t ≤ 30

t ≤ 15

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How many groups of 3/4 are in each of the following questions?
marysya [2.9K]

Answer:

12 1/3

Step-by-step exp

First, you need to add up 11/4 and

6 1/2

11/ 4 + 6 1/2 = 11/4 + 13/2 = 37 / 4

To find how many 3/4 we have in 37/4, we simply dividw 37/4 by 3/4

37/4 ÷ 3/4

= 37/4 × 4/3 (4 will cancel out 4)

= 37/3

=12 1/3

3 0
3 years ago
5 times marys age is the same as 28 less than 7 times her age. Find her age
Gnom [1K]

setup a simple algebraic equation and solve.

5x = 7x-28

-5x   -5x

0=2x-28

+28  +28

28=2x

Now divide both sides by 2 and you get that she is 14

3 0
3 years ago
Read 2 more answers
simplify 1 76/100 if you can thank you and I love you also I will thank you and refer all my friends to you look up how to basic
Galina-37 [17]
The answer is 1 19/25.

8 0
3 years ago
In the △ABC, the height AN = 24 in, BN = 18 in, AC = 40 in. Find AB and BC. Consider all possible cases. Case 1 : N∈BC, AB = __,
aivan3 [116]

Answer:

Case 1:

AB = 30

BC = 50

Case 2:

AB = 15.9

BC = 36.7

Case 3: Not possible

Step-by-step explanation:

Given

See attachment for illustration of each case

Required

Find AB and BC

Case 1:

Using Pythagoras theorem in ANB, we have:

AB^2 = AN^2 + BN^2

This gives:

AB^2 = 24^2 + 18^2

AB^2 = 576 + 324

AB^2 = 900

Take square roots of both sides

AB = \sqrt{900

AB = 30

To calculate BC, we consider ANC, where:

AC^2 = AN^2 + NC^2

40^2 = 24^2 + NC^2

1600 = 576 + NC^2

Collect like terms

NC^2 = 1600 - 576

NC^2 = 1024

Take square roots

NC = \sqrt{1024

NC = 32

So:

BC = NC + BN

BC = 32 + 18

BC = 50

Case 2:

Using Pythagoras theorem in ANB, we have:

AN^2 = AB^2 + BN^2

This gives:

24^2 = AB^2 + 18^2

576 = AB^2 + 324

Collect like terms

AB^2 = 576 - 324

AB^2 = 252

Take square roots of both sides

AB = \sqrt{252

AB = 15.9

To calculate BC, we consider ABC, where:

AC^2 = AB^2 + BC^2

40^2 = 252 + BC^2

1600 = 252 + BC^2

Collect like terms

BC^2 = 1600 - 252

BC^2 = 1348

Take square roots

BC = \sqrt{1348

BC = 36.7

Case 3:

This is not possible because in ANC

The hypotenuse AN (24) is less than AC (40)

3 0
2 years ago
Find the missing value to the nearest hundredth. cos_= 6/19
Olenka [21]

Let , missing value(_)=A

As, it is given that ,

CosA=\frac{6}{19}\\\\ Cos A=0.3158\\\\ A=72 {\text{Degree}}

To convert the value of A into Radians,

360°=2 π Radians

1 {\text{degree}}=\frac{\pi}{180}\\\\72 {\text{Degree}} =\frac{72\times 22}{180 \times 7}\\\\=1.2571

So, missing value to the nearest hundredth= 1.26 Radians

5 0
3 years ago
Read 2 more answers
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