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Vera_Pavlovna [14]
2 years ago
10

I WILL MARK BRAINLIEST! Solve for X

Mathematics
2 answers:
NARA [144]2 years ago
6 0

Answer:

Step-by-step explanation:

You are to assume in both problems that the two triangles are similar. That is a very dangerous assumption -- especially in later math classes. But in this case, there is no other way to do the problem. The two sets of triangles look like they are proportional.  So set up two ratios that are = to each other

On the left

long side small triange / long side large triangle = base small triangle / base large triangle

On the right

hypotenuse/longest leg = hypotenuse / longest leg.

Problem A

Set up the similar Proportion

5/40 = x/20                Cross Multiply

40x = 20*5

40x = 100                   Divide by 40

x = 100/40

x = 2.5

Problem B

Again set up the similar triangle proportion

15/10 = x/2                  Multiply by 2

15*2/10 = x              

3 = x

Nostrana [21]2 years ago
5 0
For the first one x=2.5
for the second one x=3
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Please help.........​
Alex

Answer:

- \frac{61}{11}

Step-by-step explanation:

\frac{x}{y} = \frac{5}{6} ( cross- multiply )

6x = 5y ( divide both sides by 6 )

x = \frac{5}{6} y

Then

\frac{5x+6y}{5x-6y} ← substitute x = \frac{5}{6} y into the expression

= \frac{\frac{25}{6}y+6y }{\frac{25}{6}y-6y }

= \frac{\frac{61}{6}y }{-\frac{11}{6}y }

= \frac{\frac{61}{6} }{-\frac{11}{6} }

= \frac{61}{6} × - \frac{6}{11}

= - \frac{61}{11}

3 0
3 years ago
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S_A_V [24]
2 divided by 5 is .4
6 0
3 years ago
Read 2 more answers
Quadrilateral ABCD has vertices A(-3, 1) B(0,4) C(4,0) D(1, -3).
Rina8888 [55]
I think the correct answer is D 1,-3
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5 0
3 years ago
A meter is 3.37 inches more than a yard swimmer a swims 100 meters and swimmer b swims 100 yeards how many more feet did swimmer
olga_2 [115]
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Swimmer b swims 100 yards, which is 300 feet

Swimmer a swam 28.07 feet.


4 0
3 years ago
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