Answer:
$367.87
Step-by-step explanation:
![P[(1 + r/100n)]^nt](https://tex.z-dn.net/?f=P%5B%281%20%2B%20r%2F100n%29%5D%5Ent)
![(2300)[(1 + (2.12)/100n)]^(52)(7)](https://tex.z-dn.net/?f=%282300%29%5B%281%20%2B%20%282.12%29%2F100n%29%5D%5E%2852%29%287%29)





has only one critical point at

. The function has Hessian

which is positive definite for all

, which means

attains a minimum at the critical point with a value of

.
To find the extrema (if any) along the boundary, parameterize it by

and

, with

. On the boundary, we have


Find the critical points along the boundary:


Respectively, plugging these values into

gives 11, 47, 43, and 47. We omit the first and third, as we can see the absolute extrema occur when

.
Now, solve for

for both cases:


so

has two absolute maxima at

with the same value of 47.
Answer:
-0.954(rounded)
Step-by-step explanation:
first write it in number form
√2(3)-√27
the exact form will be 3√2-3√27 = -0.954(rounded)
Let the cost price of article be x :
x + x × ( 15/100 ) = 2300
x + x × ( 5 × 3 / 5 × 20 ) = 2300
x + x × ( 3 / 20 ) = 2300
x + ( 3 × x / 20 ) = 2300
x + ( 3x / 20 ) = 2300
( 20x / 20 ) + ( 3x / 20 ) = 2300
20x + 3x / 20 = 2300
23x / 20 = 2300
Multiply both sides by 20
( 23x / 20 ) × 20 = 2300 × 20
23x = 2300 × 20
23x = 23 × 2000
Divide both sides 23
23x ÷ 23 = ( 23 × 2000 ) ÷ 23
x = Rs 2000