They would be 4 more points because it’s less then on their essay but okay yeah
To determine the total distance traveled by an object in constant speed, just multiply the speed by the time. So, for the car, the total distance traveled is,
distance by car = (20 m/s)(5s) = 100 m
For decelerating object, the distance traveled is,
distance = Vt - (at^2)/2
For the truck,
distance by truck = (20 m/s)(10s) - (2m/s^2)((10s)^2)/2 = 100 m
Relatively, both have traveled the same distance.
1.) y+6=3(x+2) C
y+6=3x+6
y=3x+6-6
y=3x+6
2.) y=1/2(x+8)-2 B
y=1/2x+4-2
y=1/2x+2
3.) y+1=1(x-3) E
y+1=x-3
y=x-3-1
y=x-4
4.) -4x+y=-2 A
y=-4x-2
5.) 2x-4y=-4 F
-4y=-2x-4
y=-2/-4x-4/-4
y=2/4x+4/4
y=1/2x+1
6.) 2x+4y=8 D
4y=-2x+8
y=-2/4x+8/4
y=-1/2x+4/2
y=-1/2x+2
A square has two parallel sides and four right angles.
Answer:
231
Step-by-step explanation:
=
42÷2= 21
9×21= 189
189 students total
42 6th graders