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Mice21 [21]
3 years ago
8

What does the expression l∙w represent

Mathematics
1 answer:
cluponka [151]3 years ago
4 0
It represents Length times width
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The height, h, in feet of a gold ball above the ground after being hit into the air is given by the equation. H=-16t2+64t, where
stiv31 [10]

Answer:

4 seconds

Step-by-step explanation:

Given : H = -16t^{2} +64t

To Find: How many seconds does it take for the golf ball to hit the ground?

Solution :

Since we are given an equation : H = -16t^{2} +64t

Where H denotes height

t denotes the number of seconds elapsed since the ball was hit.

When he golf ball to hit the ground at that time the height becomes 0

So, put H = 0 in the equation

H = - 16t^{2} +64t

0 = - 16t^{2} +64t

16t^{2} = 64t

16t = 64

t =\frac{64}{16}

t =4

Thus it take 4 seconds for the golf ball to hit the ground

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3 years ago
Evaluate 4(5 - 8) - 7
Sholpan [36]

Answer:

Step-by-step explanation:

The answer is 5 :)

4 0
3 years ago
Two angles with the sum of 90 degrees picture
UkoKoshka [18]
Either a rectangle or square
8 0
3 years ago
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Prove that sinxtanx=1/cosx - cosx
maks197457 [2]

Answer:

See below

Step-by-step explanation:

We want to prove that

\sin(x)\tan(x) = \dfrac{1}{\cos(x)} - \cos(x), \forall x \in\mathbb{R}

Taking the RHS, note

\dfrac{1}{\cos(x)} - \cos(x) = \dfrac{1}{\cos(x)} - \dfrac{\cos(x) \cos(x)}{\cos(x)} = \dfrac{1-\cos^2(x)}{\cos(x)}

Remember that

\sin^2(x) + \cos^2(x) =1 \implies 1- \cos^2(x) =\sin^2(x)

Therefore,

\dfrac{1-\cos^2(x)}{\cos(x)} = \dfrac{\sin^2(x)}{\cos(x)} = \dfrac{\sin(x)\sin(x)}{\cos(x)}

Once

\dfrac{\sin(x)}{\cos(x)} = \tan(x)

Then,

\dfrac{\sin(x)\sin(x)}{\cos(x)} = \sin(x)\tan(x)

Hence, it is proved

5 0
3 years ago
HELP ME ASAP PLEASEEEEEEE
Vlad [161]

Answer: a) about 450

Step-by-step explanation:

50 multiplied by 9 is 450 and its asking for an approximate so it would be anything near 450

3 0
3 years ago
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