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REY [17]
3 years ago
11

A rectangular garden has length and width as given by the expressions below.

Mathematics
1 answer:
anyanavicka [17]3 years ago
6 0

Answer:

(8 - 42x - 56y -12xy) is you're answer.

Step-by-step explanation:

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Is -0.2222222... terminating or repeating
frozen [14]

Answer:

repeating

Step-by-step explanation:

If a decimal continues to go on forever, it is called repeating, but if a decimal stops, it is called terminating.

5 0
3 years ago
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Log10(2x+1)-log10(3x+2)=1​
SIZIF [17.4K]

Answer:

x= -2

Step-by-step explanation:

If you are asking for the subtraction of the equations, then I have given the correct answer. If this is not what you are looking for, please state clearly what you are looking for and I will be happy to help!!

4 0
3 years ago
Need help ASAP!!!!!!!
marin [14]

Answer:

1. 3   2. 16

Step-by-step explanation:

3x+2/y, x = 3 and y = 6

3(3)/6

Factor the number

3*3*2/3*2

Cancel the common factor (3)

3*2/2

Cancel the common factor (2)

3/1

Simplify

=3

(4a)^3/(b-2), a = 2, b = 4

(4(2)^3/(4-2)

Subtract the numbers:

2^3 * 4/2

Apply exponent rule (a^b*a^c=a^b+c)

= 2^3+1

Add the numbers:

2^4

Simplify:

=16

8 0
3 years ago
(1/1+sintheta)=sec^2theta-secthetatantheta pls help me verify this
Xelga [282]

Answer:

See Below.

Step-by-step explanation:

We want to verify the equation:

\displaystyle \frac{1}{1+\sin\theta} = \sec^2\theta - \sec\theta \tan\theta

To start, we can multiply the fraction by (1 - sin(θ)). This yields:

\displaystyle \frac{1}{1+\sin\theta}\left(\frac{1-\sin\theta}{1-\sin\theta}\right) = \sec^2\theta - \sec\theta \tan\theta

Simplify. The denominator uses the difference of two squares pattern:

\displaystyle \frac{1-\sin\theta}{\underbrace{1-\sin^2\theta}_{(a+b)(a-b)=a^2-b^2}} = \sec^2\theta - \sec\theta \tan\theta

Recall that sin²(θ) + cos²(θ) = 1. Hence, cos²(θ) = 1 - sin²(θ). Substitute:

\displaystyle \displaystyle \frac{1-\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta \tan\theta

Split into two separate fractions:

\displaystyle \frac{1}{\cos^2\theta} -\frac{\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta\tan\theta

Rewrite the two fractions:

\displaystyle \left(\frac{1}{\cos\theta}\right)^2-\frac{\sin\theta}{\cos\theta}\cdot \frac{1}{\cos\theta}=\sec^2\theta - \sec\theta \tan\theta

By definition, 1 / cos(θ) = sec(θ) and sin(θ)/cos(θ) = tan(θ). Hence:

\displaystyle \sec^2\theta - \sec\theta\tan\theta \stackrel{\checkmark}{=}  \sec^2\theta - \sec\theta\tan\theta

Hence verified.

8 0
3 years ago
Cora is wrapping her sister's birthday present. She needs to cut a 47-centimeter piece of ribbon into 5 equal parts. How long wi
snow_lady [41]

Answer:

Step-by-step explanation:

If its fractions, you would do 5/47

8 0
3 years ago
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