The momentum formula is
p = m*v
where,
p = momentum (not sure why p is chosen but many physics books tend to pick this letter)
m = mass in kilograms
v = velocity in meters per second
So let's calculate the momentum for the 4500 kg vehicle
p = m*v
p = 4500*85
p = 382500 kg m/s
And let's do the same for the 3700 kg vehicle
p = m*v
p = 3700*85
p = 314500 kg m/s
Answer:
$7,925.53
Step-by-step explanation:
We'll have to use the compound interest formula: A = P(1 + r/n)ⁿˣ
A = final amount (?)
P = starting amount (5700)
r = rate
n = times applied (12 since its monthly and there 12 months in a year)
x = years (12)
A = 5700(1 + 0.0275/12)¹⁴⁴
A = 7925.525498629932
Answer:
Step-by-step explanation:
Given
Parallel lines A and B
Required
Find x
For A and B to be parallel, then 5x + 9 and 6x - 2 are alternate interior angles
And alternate interior angles are always equal
This means that
Collect like terms
Multiply both sides by -1
Answer:
As the calculated value of z does not lie in the critical region the null hypothesis is accepted that the GPA mean of the night students is the same as the GPA mean of the day students.
Step-by-step explanation:
Here n= 20
Sample mean GPA = x`= 2.84
Standard mean GPA = u= 2.55
Standard deviation = s= 0.45.
Level of Significance.= ∝ = 0.01
The hypothesis are formulated as
H0: u1=u2 i.e the GPA of night students is same as the mean GPA of day students
against the claim
Ha: u1≠u2
i.e the GPA of night students is different from the mea GPA of day students
For two tailed test the critical value is z ≥ z∝/2= ± 2.58
The test statistic
Z= x`-u/s/√n
z= 2.84-2.55/0.45/√20
z= 0.1441
As the calculated value of z does not lie in the critical region the null hypothesis is accepted that the GPA mean of the night students is the same as the GPA mean of the day students.
Well, let's use the Euclidean algorithm:
164 = 4×37 + 16
37 = 2×16 + 5
16 = 3×5 + 1
Then working backwards,
1 = 16 - 3×5
1 = 16 - 3×(37 - 2×16) = 7×16 - 3×37
1 = 7×(164 - 4×37) - 3×37 = 7×164 - 31×37
so that x = 7 and y = -31.
