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ivolga24 [154]
3 years ago
11

What is the best estimate length of a football

Mathematics
1 answer:
Ne4ueva [31]3 years ago
5 0
11 to 11.2 inches Is an estimate length of a football
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Solve -17-2(×-4)-5(4×-7)
mina [271]
26-22x is the correct answer
8 0
3 years ago
Which of the following statement(s) describes the rate of change of f over the interval 1.5 ≤ x ≤ 3? Select all that apply.
Vesnalui [34]

2 Answers: Choice B and Choice C

The rate of change is 2.

The rate of change is constant.

======================================================

Explanation:

The first point on the left is when x = 1.5 and it has a height of y = 1

The point (1.5, 1) is on the line.

So is the point (3,4) for similar reasoning.

Compute the slope between those points

m = (y2-y1)/(x2-x1)

m = (4-1)/(3-1.5)

m = 3/(1.5)

m = 2

The slope is 2, which is the same as saying the rate of change is 2. This only applies when x > 1 of which the interval 1.5 ≤ x ≤ 3  is a part of.

Since the slope stays at 2 on the interval 1.5 ≤ x ≤ 3, this means we consider the slope to be constant. If the curve bended at all on this interval, then it wouldn't be a constant slope.

6 0
1 year ago
Part A A high school athlete ran the 100 meter sprint in 13.245 seconds. Round the time to the nearest tenth.Part B Explain how
amid [387]

Answer:

t = 13.2 s

Step-by-step explanation:

Given that,

An athlete ran the 100 meter sprint in 13.245 seconds. We need to round off the time to the nearest tenth.

Here, t = 13.245 s

In order to round off to the nearest tenth, thousandths place and hundredth place gets eliminated.

So, t = 13.2 s

So, time is 13.2 seconds.

5 0
3 years ago
Use Gauss-Jordan elimination to solve the following linear system.
marysya [2.9K]
Just put the coefients in to a matrix

1x-6y-3z=4
-2x+0y-3z=-8
-2x+2y-3z=-14

\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\-2&2&-3|-14\end{array}\right]
mulstiply 2nd row by -1 and add to 3rd
\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\0&2&0|-6\end{array}\right]
divde last row by 2
\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\0&1&0|-3\end{array}\right]
multiply 2rd row by 6 and add to top one
\left[\begin{array}{ccc}1&0&-3|-14\\-2&0&-3|-8\\0&1&0|-3\end{array}\right]
multiply 1st row by -1 and add to 2nd
\left[\begin{array}{ccc}1&0&-3|-14\\-3&0&0|6\\0&1&0|-3\end{array}\right]
divide 2nd row by -3
\left[\begin{array}{ccc}1&0&-3|-14\\1&0&0|-2\\0&1&0|-3\end{array}\right]
mulstiply 2nd row by -1 and add to 1st row
\left[\begin{array}{ccc}0&0&-3|-12\\1&0&0|-2\\0&1&0|-3\end{array}\right]
divide 1st row by -3
\left[\begin{array}{ccc}0&0&1|4\\1&0&0|-2\\0&1&0|-3\end{array}\right]

rerange
\left[\begin{array}{ccc}1&0&0|-2\\0&1&0|-3\\0&0&1| 4\end{array}\right]

x=-2
y=-3
z=4
(x,y,z)
(-2,-3,4)

B is answer
7 0
2 years ago
A sailboat traveled 30 miles in 2.5 hours. At the same speed, how far can the boat sail in another 4.5 hours ?
Ivanshal [37]

54 miles

using the formula

speed = \frac{distance}{time} = \frac{30}{2.5} = 12 mph

continuing at 12 mph then

distance = speed × time = 12 × 4.5 = 54 miles


8 0
3 years ago
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