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belka [17]
3 years ago
10

Help I can’t figure out how to do zero exponents

Mathematics
1 answer:
Orlov [11]3 years ago
4 0

Anything (except 0) to the 0 power is equal to 1.

8^0  = 1

(-8)^0 = 1

24781297429879741^0 = 1

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Select the statement that best justifies the conclusion based on the given information. Definition of bisector. Definition of mi
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This may be wrong I cant realy tell from the text 

midpoint is though any two different points 
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8.35 &lt; 3x +18.75<br> Pls help
zzz [600]

Step-by-step explanation:

8.35 < 3x + 18.75

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Greg is training for the upcoming basketball season. His schedule this week allows him to complete at most 8 training sessions.
Sav [38]

Answer:

\left\{\begin{array}{l}x+y\le360\\ \\\dfrac{x}{45}+\dfrac{y}{35}\le 8\end{array}\right..

Step-by-step explanation:

Let x minutes be the time spent on skills and y minutes be the time spent on conditioning that Greg can complete this week.

1. To avoid excess fatigue, his coach requires Greg to spend no more than 360 minutes training in any week, then

x+y\le 360.

2. When Greg trains, he either spends 45 minutes on skills or 35 minutes on conditioning. If Greg spends x minutes on skills, then \dfrac{x}{45} is the number of skills training sessions. If Greg spends y minutes on conditioning, then \dfrac{y}{35} is the number of conditioning training sessions. His schedule this week allows him to complete at most 8 training sessions, then

\dfrac{x}{45}+\dfrac{y}{35}\le 8.

Therefore, the following system of inequalities can be used to determine the time spent on skills, x, and the time spent on conditioning, y, that Greg can complete this week

\left\{\begin{array}{l}x+y\le360\\ \\\dfrac{x}{45}+\dfrac{y}{35}\le 8\end{array}\right..

3 0
3 years ago
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Please help me thank you
masya89 [10]

Answer:

obtuse

Step-by-step explanation:

the triangle is larger than a 90 degree angle

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3 years ago
Common denominator of 3, 4, 5.
gtnhenbr [62]

Answer:

The LCM of 3,4,5 3 , 4 , 5 is 2⋅2⋅3⋅5=60 2 ⋅ 2 ⋅ 3 ⋅ 5 = 60 .

Step-by-step explanation:

6 0
3 years ago
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