I belive what you did wrong is that you didint show your work so what you have to do is explain how to do the problem with equations or explain in word form if i were you i would show my work in equations if you need help on how to set it up contact me.
Answer:
xy1
Step-by-step explanation:
Correct option is C)
Given two equations are 2x+y+4=0 and x=3y+7=0
let us consider 2 equations ax+by+c=0 and mx+ny+p=0
By cross multiplication method ,the equations obtained will be ,
b×p−n×c
x
=
c×m−a×p
y
=
a×n−b×m
1
Thus comparing it with given 2 equations we obtain:
7−12
x
=
4−14
y
=
6−1
1
M=5
9x5=45
45/9=5
hope this helps you out
Step-by-step explanation:
180-124=56°
180-56-2x-(180-6x)=0
180-56-2x-180+6x=0
-56+4x=0
4x=56
x=14°
........
2x=28
6x=84
Answer:
y=-1/4x+3 is the answer.
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