Dividing the given polynomial by (x -6) gives quotient Q(x) and remainder 5 then for Q(-6) = 3 , P(-6) = -31and P(6) =5.
As given in the question,
P(x) be the given polynomial
Dividing P(x) by divisor (x-6) we get,
Quotient = Q(x)
Remainder = 5
Relation between polynomial, divisor, quotient and remainder is given by :
P(x) = Q(x)(x-6) + 5 __(1)
Given Q(-6) = 3
Put x =-6 we get,
P(-6) = Q(-6)(-6-6) +5
⇒ P(-6) = 3(-12) +5
⇒ P(-6) =-36 +5
⇒ P(-6) = -31
Now x =6 in (1),
P(6) = Q(6)(6-6) +5
⇒ P(6) = Q(6)(0) +5
⇒ P(6) = 5
Therefore, dividing the given polynomial by (x -6) gives quotient Q(x) and remainder 5 then for Q(-6) = 3 , P(-6) = -31and P(6) =5.
The complete question is:
Dividing the polynomial P(x) by x - 6 yields a quotient Q(x) and a remainder of 5. If Q(-6) = 3, find P(-6) and P(6).
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Answer:
2/5 of 75 is 30 thats all i have for because i am haveing trouble with the same question
Step-by-step explanation:
Answer:
Step-by-step explanation:
The orange divisor(s) above are the prime factors of the number 1,620. If we put all of it together we have the factors 2 x 2 x 3 x 3 x 3 x 3 x 5 = 1,620. It can also be written in exponential form as 22 x 34 x 51.
It’s actually B Bc the little 1 by the 10 is meaning that you are gonna multiply 10x10 one time. Then multiply by 7. 10x10=100 100x7=700 so there for your answer is B
Answer:
B would be the answer for this question.
Step-by-step explanation:
