Answer:
The coefficient of static friction between the coin and the turntable is 0.51
Explanation:
at the time of the slip:
centripetal force = frictional force
mv^2/r = x*m*980
v^2/r = 980x
x = v^2/980r
= [(120)^2]/[980*29]
= 0.51
Therefore, The coefficient of static friction between the coin and the turntable is 0.51
Answer:
im 99% sure its initial disturbance
Explanation:
A) The friction force while the box is stationary is (the coefficient of static friction)*(the normal force). In this case, the normal force is equal to the gravitational force, or the weight. To move the box, we need a minimum horizontal force that is equal to the friction force. The weight is (500 kg)*(9.81 m/s^2)= 4905 N. So, (0.45)*(4905 N) = 2207.25 N.
b) The acceleration will be the horizontal force - the kinetic friction force (since they act in opposite directions) divided by the mass. Kinetic friction force = (coefficient of kinetic friction)*(normal force or weight).
F(net) = (2207.25 N)-(0.30)(4905 N) = 735.75 N
a = (735.75 N)/(500kg)= 1.4715 m/s^2
Answer:
B
Explanation:
A bicameral system describes a government that has a two-house legislative system, such as the House of Representatives and the Senate that make up the U.S. Congress.
Hi there! :)
We can begin by doing a summation of forces on the ball. In the horizontal direction, we have the force of tension:
The tension force results in a centripetal force experienced by the ball. The equation of centripetal force is equivalent to:
= Centripetal force (N)
m = mass of ball (0.22 kg)
ω = angular speed of ball(? rad/sec, must convert rpm to rad/sec)
r = radius/length of string (1.0 m)
We must begin by converting rpm to rad/sec:
Now, we can set tension equal to the centripetal force and solve. 
