A theoretical perspective is a set of assumptions about reality that inform the questions we ask and the kinds of answers we arrive as a result.
Answer:
There is the conservation of energy in a harmonic oscillator. As a result, the system amplitude will remain constant. The dissipative forces (i.e. friction) lead to loss of energy in different forms and the system amplitude is reduced due to the reduction in both kinetic and potential energies at the end of each oscillation.
The external forces acting on a driving mechanism must be accounted for at all times. In this case, there is a loss of energy because dissipative forces can be returned back to the system in the presence of the driving to account for the loss in energy.
Explanation:
There is the conservation of energy in a harmonic oscillator. As a result, the system amplitude will remain constant. The dissipative forces (i.e. friction) lead to loss of energy in different forms and the system amplitude is reduced due to the reduction in both kinetic and potential energies at the end of each oscillation.
The external forces acting on a driving mechanism must be accounted for at all times. In this case, there is a loss of energy because dissipative forces can be returned back to the system in the presence of the driving to account for the loss in energy.
Answer:
2400 J
Explanation:
Latent heat: This is also called hidden heat, it is the heat that is not detectable by the thermometer.
From the question,
Q = cm.................. Equation 1
Where Q = Energy, c = specific latent heat of the liquid, m = mass of the liquid.
Given: c = 4000 J/kg, m = 600 g =( 600/1000) kg = 0.6 kg
Substitute these values into equation 1
Q = 4000×0.6
Q = 2400 J
Hence the energy required is 2400 J
The correct choice is D, and it's convection, not conversion.
Answer:
(a) Magnitude of static friction force is 109 N
(b) Minimum possible value of static friction is 0.356
Solution:
As per the question;
Horizontal force exerted by the girl, F = 109 N
Mass of the crate, m = 31.2 kg
Now,
(a) To calculate the magnitude of static friction force:
Since, the crate is at rest, the forces on the crate are balanced and thus the horizontal force is equal to the frictional force, f:
F = f = 109 N
(b) The maximum possible force of friction between the floor and the crate is given by:
![f_{m} = \mu_{s}N](https://tex.z-dn.net/?f=f_%7Bm%7D%20%3D%20%5Cmu_%7Bs%7DN)
where
N = Normal reaction = mg
Thus
![f_{m} = \mu_{s}mg](https://tex.z-dn.net/?f=f_%7Bm%7D%20%3D%20%5Cmu_%7Bs%7Dmg)
For the crate to remain at rest, The force exerted on the crate must be less than or equal to the maximum force of friction.
![f\leq f_{m}](https://tex.z-dn.net/?f=f%5Cleq%20f_%7Bm%7D)
![f \leq \mu_{s}mg](https://tex.z-dn.net/?f=f%20%5Cleq%20%5Cmu_%7Bs%7Dmg)
![109 \leq \mu_{s}\times 31.2\times 9.8](https://tex.z-dn.net/?f=109%20%5Cleq%20%5Cmu_%7Bs%7D%5Ctimes%2031.2%5Ctimes%209.8)
![\mu_{s}\geq 0.356](https://tex.z-dn.net/?f=%5Cmu_%7Bs%7D%5Cgeq%200.356)