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MariettaO [177]
3 years ago
15

Eliminate the parameter. x = t^2 + 1, y = t^2 - 1.

Mathematics
1 answer:
Maksim231197 [3]3 years ago
7 0

Answer:

Eliminating the parameter, the equation is y = x - 2

Step-by-step explanation:

We are given the following parametric equations:

x = t^2 + 1

y = t^2 - 1

We want to eliminate the parameter t. From the first equation:

x = t^2 + 1

t^2 = x - 1

Replacing in the second equation:

y = x - 1 - 1

y = x - 2

Eliminating the parameter, the equation is y = x - 2

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Answer:

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Step-by-step explanation:

The given two equations are :

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\frac{3}{4}(x-12)=12\\\\\text{On cross multiplication, we get}\\\\\implies 3\times (x-12)=12\times 4\\\implies 3x -36=48\\\implies 3x=48+36\\\implies 3x=84\\\bf\implies x=28

Solving equation (2) to obtain value of y. We have,

\frac{3}{4}\cdot y-12=12\\\\\implies \frac{3}{4}\cdot y=12+12\\\\\implies \frac{3}{4}\cdot y=24\\\\\text{On cross multiplicatrion, We get}\\\implies 3\cdot y=24\times 4\\\implies 3y = 96\\\bf\implies y=32

Hence, The required value of x = 28

And The value of y = 32

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