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2 years ago

45% of 60 Whats the answer? Please add a model. If you can.

2 answers:

6 0

45% times 60 = 27 because it you think of it the way I showed you it would have to be that answer remember
When doing percents find out half witch is 50 % then find out 10% of 60 add what you got for both of them and you get for both of them and your ansewr

Assoli18 [71]2 years ago

5 0

Hi dear

100% - 60
45% - X

x = (60×45)/100 = 2700/100 = 27

the second way to calculate it, is simply multiplying them with each other:

(45%)(60)= (45/100)(60) = 27

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In an attempt to escape a desert island, a castaway builds a raft and sets out to sea. The wind shifts a great deal during the d

nikdorinn [45]

Answer:

R = 7,34 km

Ф = 63,43° north of east

Step-by-step explanation:

Let´s analyze each movement and find its perpendicular components. Then, we are going to add the components along the x and y axes to get the resultant and finally to calculate its magnitude and direction.

To determine the perpendicular components, we will use right triangles trigonometrics ratios.

Please see images for each displacement in attached file.

Displacement A: 2.50 km and 45° north of west

Ax= AcosФ = 2.50cos45° = 1.77 km (neg. direction)

Ay= AsenФ = 2.50sen45° = 1.77 km (pos. direction)

Displacement B: 4.70 km and 60° south of east

Bx= BcosФ = 4.70cos60° = 2,35 km (pos. direction)

By= BsenФ = 4.70sen60° = 4,07 km (neg. direction)

Displacement C: 1.30 km and 25° south of west

Cx= CcosФ = 1.30cos25° = 1,18 km (neg. direction)

Cy= CsenФ = 1.30sen25° = 0.55 km (neg. direction)

Displacement D: 5.10 km due east (0°)

Dx= DcosФ = 5.10 km (pos. direction)

Dy= DsenФ = 0 km

Displacement E: 1.70 km and 5° east of north

Ex= EsenФ = 1.70sen5° = 0,15 km (pos. direction)

Ey= EcosФ = 1.70cos5° = 1.69 km (pos. direction)

Displacement F: 7.20 km and 55° south of west

Fx= FcosФ = 7.20cos55° = 4.13 km (neg. direction)

Fy= FsenФ = 7.20sen55° = 5.90 km (neg. direction)

Displacement G: 2.80 km and 10° north of east

Gx= GcosФ = 2.80cos10° = 2.76 km (pos. direction)

Gy= GsenФ = 2.80sen10° = 0.49 km (pos. direction)

Now, we add the components along the x- and y- axis to find the components of the resultant (R):

Rx = Ax + Bx + Cx + Dx + Ex + Fx + Gx

Ry = Ay + By + Cy + Dy + Ey + Fy + Gy

Therefore,

Rx= (-1.77)+(2.35)+(-1.18)+(5.10)+(0.15)+(-4.13)+(2.76)

Ry= (1.77)+(-4.07)+(-0.55)+(0)+(1.69)+(-5.90)+(0.49)

Note: minus (-) symbol to negative directions

Rx = 3.28 km

Ry = - 6.57 km

Let´s use the Theorem of Pythagoras to find the magnitud ot the resultant:

$R = \sqrt{Rx^{2} +Ry^{2} }$

$R =\sqrt{(3.28)^{2}+(-6.57)^{2} }$

R = 7,34 km

To find the direction of the resultant:

tanФ = $\frac{Ry}{Rx}$

tanФ = $\frac{6.57}{3.28}$

tanФ = 2.00

Ф = tan-1 (2.00)

Ф = 63,43° north of east

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3 0

3 years ago

How many quarter pound 1/4 packets can a garden shop make out of 8 pounds of the plant food

Step2247 [10]

32

Sorry, I couldn't really think of a way to explain but the best I can is by multiplying the 4 by 8 to get the answer of 32

8 0

3 years ago

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9u2v and which term are like terms? A.6u2, B.9uv2, C.15u2v, D.13u2v2

irina1246 [14]

It is essential that you use the symbol " ^ " to denote exponention. See the following changes I have made.

9u^2v and which term or terms are like terms? 15u^2v. Why? because both have "u^2" in them.

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3 years ago

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Free brainless give away

Fed [463]

Answer:

Brainless bruv I gonna say that's a insult but ok

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3 years ago

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The vertices of a triangle are A(2,4),B(-1,-3),and C(3,6). Find the new vertices. Use the rule (x,y) >>>(x-3,y+5)to tra

Mama L [17]

Answer:

A(-1,9), B(-4,2) and C(0,11)

Step-by-step explanation:

The vertices of a triangle are A(2,4),B(-1,-3),and C(3,6).

To translate, we use the rule (x,y) >>>(x-3,y+5)

For Vertex A(2,4),

The new vertex is (2-3, 4+5)=(-1,9)

For Vertex B(-1,-3)

The new vertex is (-1-3,-3+5)=(-4,2)

For Vertex C(3,6)

The new vertex is (3-3,6+5)=(0,11)

After translation of Vertex A, B and C by the given rule, the new points are A(-1,9), B(-4,2) and C(0,11)

8 0

3 years ago