Which line segments are a radius of Y? RX SW SY TY
1 answer:
You might be interested in
Slope-intercept form:
y = mx + b
"m" is the slope, "b" is the y-intercept (the y value when x = 0)
You need to find "m" and "b"
1.) For lines to be perpendicular, their slopes have to be the opposite/negative reciprocal (flipped sign and number)
For example:
slope is 2
perpendicular line's slope is -1/2
slope is -2/3
perpendicular line's slope is 3/2
The given line's slope is -4, so the perpendicular line's slope is 1/4.
y = 1/4x + b
To find "b", you can plug in the point (4, -2) into the equation
y = 1/4x + b
-2 = 1/4(4) + b
-2 = 1 + b
-3 = b
2.) To find "m", use the slope formula and plug in the two points:
y = -3/2x + b
Plug in one of the points to find "b"
y = -3/2x + b
-1 = -3/2(4) + b
-1 = -6 + b
5 = b
3.) y-intercept: 5 (since the given equation's y-intercept is 5)
I'm confused with what they mean by "steep", so I'll try to update this later unless someone else has an answer
So I looked it up, and it says that a steep slope is a line that is more vertical [if that makes sense]. So you could do a slope of +3 (more than 3, like 4, 5, 6...) because the given line's slope is 3, and you need a new line that is more steeper(vertical)