A function is shown f=(x)=x^2+ 2X-3

Mathematics

1 answer:

Brut [27]3 years ago

8 0

Answer:

x intercepts at (-3,0), and (1,0)

there is a minimum at (-1,-4)

Step-by-step explanation:

Please see attached image for the requested graph of the function $f(x) = x^2+2x-3$ , and observe that the crossings of the x-axis are at the points (-3,0), and (1,0) , marked in red in the image.

We can also see that there is no maximum, but a minimum value, and located at the point (-1,-4) [marked in green in the image]

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