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Keith_Richards [23]

3 years ago

10

John owes a debt of $500 to his landlord. His father has agreed to pay 3/5

2 answers:

Furkat [3]3 years ago

8 0

John’s father will pay $300.

If you divide $500 into 5 equal parts, each part will be comprised of $100. In other words, 1/5 of $500 is $100. This is proven because $100 • 5 = $500.

But since you are trying to find 3/5 of $500, (not 1/5, which is what we just found). This means we must find the total value of 3 of the five equal parts. To do this, multiply
$100 • 3, since $100 is 1/5 of $500.
$100 • 3=$300, so the answer is B. Johns father will pay $300.

inn [45]3 years ago

7 0

Answer:

300

Step-by-step explanation:

500 x 3/5

=300

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40 POINTS is (4,7) a solution of equations? Explain your answer 2x+4y=36 3x-4y=-6

dsp73

<span>2x + 4y = 36
3x - 4y = -6
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5x = 30
x = 6

</span>2x+4y=36
2(6)+4y=36
12 + 4y = 36
4y = 24
y = 6

answer
<span>(6, 6) is a solution of equations
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Ilia_Sergeevich [38]

10% of 35 is 3.5
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10% of 350 is 35
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3 years ago

A ladder is leaning against a vertical wall. The distance from the top of the ladder to the base of the wall is 17 feet. The dis

Gennadij [26K]

Answer:

18.4 feet

Step-by-step explanation:

-use the formula C^2 = A^2 + B^2 for a right triangle, which is made by the ladder and the wall.

-let the ladder be C, the wall be a, the base to the bottom be b.

-substitude into the equation, which will leave us with:

C^2 = 17^2 + 7^2

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Step-by-step explanation:

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a line whose perpendicular distance from the origin is 4 units and the slope of perpendicular is 2÷3. Find the equation of the l

GrogVix [38]

Answer:

$\huge\boxed{y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{2}{3}x+\dfrac{4\sqrt{13}}{3}}$

Step-by-step explanation:

The equation of a line:

$y=mx+b$

We have

$m=\dfrac{2}{3}$

substitute:

$y=\dfrac{2}{3}x+b$

The formula of a distance between a point and a line:

General form of a line:

$Ax+By+C=0$

Point:

$(x_0,\ y_0)$

Distance:

$d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+b^2}}$

Convert the equation:

$y=\dfrac{2}{3}x+b$ |<em>subtract $y$ from both sides</em>

$\dfrac{2}{3}x-y+b=0$ |<em>multiply both sides by 3</em>

$2x-3y+3b=0\to A=2,\ B=-3,\ C=3b$

Coordinates of the point:

$(0,\ 0)\to x_0=0,\ y_0=0$

substitute:

$d=4$

$4=\dfrac{|2\cdot0+(-3)\cdot0+3b|}{\sqrt{2^2+(-3)^2}}\\\\4=\dfrac{|3b|}{\sqrt{4+9}}$

$4=\dfrac{|3b|}{\sqrt{13}}\qquad|$ |<em>multiply both sides by $\sqrt{13}$ </em>

$4\sqrt{13}=|3b|\iff3b=-4\sqrt{13}\ \vee\ 3b=4\sqrt{13}$ |<em>divide both sides by 3</em>

$b=-\dfrac{4\sqrt{13}}{3}\ \vee\ b=\dfrac{4\sqrt{13}}{3}$

Finally:

$y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{4\sqrt{13}}{3}$

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3 years ago