Answer:
Step-by-step explanation:
Given that there are six different toys and they are to be distributed to three different children.
The restraint here is each child gets atleast one toy.
Let us consider the situation as this.
Since each child has to get atleast one toy no of ways to distribute
any 3 toys to the three children each. This can be done by selecting 3 toys from 6 in 6C3 ways and distributing in 3! ways
So 3 toys to each one in 6x5x4 =120 ways
Now remaining 3 toys can be given to any child.
Hence remaining 3 toys can be distributed in 3x3x3 =27 ways
Total no of ways
= 120(27)
= 3240
Answer:
Idk if its multiple choice but you can do 1 of 2 ways theres using distance formula =√(5-3)sq+(1-4)sq
=√4+9
=√13 <--
or
3.6 units
Given: The two points that are P(5,1) and Q(3,4).
To find: The distance between these two points.
Solution: It is given that there are two points that are P(5,1) and Q(3,4).
The distance between these two points can be found out as using the distance formula that is: 3.6
Thus, the distance between the given two points is 3.6 units.
So you choose 13 or 3.6 Hope this helps :)
The second condition tells you that
is half the size of
, so
, which could be rewritten in several ways. In standard form, that would be
.
The answer A shows the integers from greatest to least
Answer:
No it's 2 Lol not 929 UwU
