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svet-max [94.6K]
3 years ago
5

Someone please help me ASAP

Mathematics
1 answer:
Yuri [45]3 years ago
8 0

Answer:

1/3

Step-by-step explanation:

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Answer: A and B I think

Step-by-step explanation:

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3 years ago
Find the slope intercept <br>(9,5),(7,-11)<br>y=​
grin007 [14]

Answer:

y=8x-67

Step-by-step explanation:

So the question is what is the equation for the following two coordinate points?

Well to start off what is the formula? The formula is called the linear equation. Which is y=mx+b. What does these letters or "variables" mean or represent?! Welp, m stands for the slope, which is "Δy over Δx." Some people call say "the change of y over x." I call it the rise over run. So it is saying y over x. The b in the linear equation is the y-intercept. The y-intercept is when the line crosses the y-axis.

With that being said, let's find the slope. But how? Well with the Δy over Δx. The formula is y₂-y₁ over x₂-x₁. With the two coordinate points we can label them.

y₂=5

y₁=(-11)

x₂=9

x₁= 7

Now let set it up into the equation of y over x

Slope =  <u> 5- (-11) </u> = <u> 5 + 11  </u> = <u>  16 </u> = 8

                  9-7         9-7          2

So we now have the slope! Which is 8! So put that into the linear equation!

y=8x+b

Next, we need to find b, the y-intercept! How do we do that well, we can figure it out by one of the coordinate points! Let use the (7, -11) point for example! Remember, x= 7 and y= (-11)

(-11) = 8(7) + b

(-11) = 56 + b

<u>-56   -56</u>

-67 =  b

We now have b, which is negative 67! So we need to put all the information we have found into the linear equation!

y=8x-67

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Find d for the arithmetic series with S17=-170 and a1=2
Irina18 [472]
So, we know the sum of the first 17 terms is -170, thus S₁₇ = -170, and we also know the first term is 2, well

\bf \textit{ sum of a finite arithmetic sequence}\\\\&#10;S_n=\cfrac{n(a_1+a_n)}{2}\qquad &#10;\begin{cases}&#10;n=n^{th}\ term\\&#10;a_1=\textit{first term's value}\\&#10;----------\\&#10;n=17\\&#10;S_{17}=-170\\&#10;a_1=2&#10;\end{cases}&#10;\\\\\\&#10;-170=\cfrac{17(2+a_{17})}{2}\implies \cfrac{-170}{17}=\cfrac{(2+a_{17})}{2}&#10;\\\\\\&#10;-10=\cfrac{(2+a_{17})}{2}\implies -20=2+a_{17}\implies -22=a_{17}

well, since the 17th term is that much, let's check what "d" is then anyway,

\bf n^{th}\textit{ term of an arithmetic sequence}\\\\&#10;a_n=a_1+(n-1)d\qquad &#10;\begin{cases}&#10;n=n^{th}\ term\\&#10;a_1=\textit{first term's value}\\&#10;d=\textit{common difference}\\&#10;----------\\&#10;n=17\\&#10;a_{17}=-22\\&#10;a_1=2&#10;\end{cases}&#10;\\\\\\&#10;-22=2+(17-1)d\implies -22=2+16d\implies -24=16d&#10;\\\\\\&#10;\cfrac{-24}{16}=d\implies -\cfrac{3}{2}=d
6 0
3 years ago
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