Ask question

Ask question

All categories

3 years ago

12

Please help!! ASAP!!!!

1 answer:

Softa [21]3 years ago

8 0

Tan(theta)= pi

Now, in order for you to find the angle (theta), you would inverse tan both the left and the right to find the value. The inverse of tan is tan^-1.

tan(theta)=pi ---> theta = tan^-1(pi)

Then, you would plug tan^-1(pi) into a calculator, giving you the value

1.26

You might be interested in

Solve equation <br><br> r/3-4=11<br><br> r = 45 <br><br> r = 35<br><br> r = 33<br><br> r = 28

Molodets [167]

Answer:

r=-11

Step-by-step explanation:

7 0

2 years ago

If you work make 15 an hour for 8 hour shift how much is that

tangare [24]

Answer:

120

Step-by-step explanation:

15*8=120

5 0

2 years ago

Read 2 more answers

BLANK + 308 + -126 = 450

fenix001 [56]

Answer:

268

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Assume that you want to test the claim that the paired sample data come from a population for which the mean difference is μd =

swat32

Answer:

Test statistic, $t_{s} = -0.603$ (to 3 dp)

Step-by-step explanation:

Deviation, d = x -y

Sample mean for the deviation

$\bar{d} = \frac{\sum x-y}{n}$

$\bar{d} = \frac{(28-6) + (31-27)+(20-26)+(25-25)+(28-29)+(27-32)+(33-33)+(35-34)}{8} \\\bar{d} = -0.625$

Standard deviation: $SD = \sqrt{\frac{\sum d^{2} - n \bar{d}^2}{n-1} }$

$\sum d^{2} = (28-26)^2 + (31-27)^2 +(20-26)^2 +(25-25)^2 +(28-29)^2 +(27-32)^2 +(33-33)^2 +(35-34)^2\\\sum d^{2} = 63$

$SD = \sqrt{\frac{63 - 8 * (-0.625)^2}{8-1} }$

SD =2.93

Under the null hypothesis, the formula for the test statistics will be given by:

$t_{s} = \frac{ \bar{d}}{s_{d}/\sqrt{n} } \\t_{s} = \frac{- 0.625}{2.93/\sqrt{8} }$

$t_{s} = -0.6033$

6 0

2 years ago

Which expression is equivalent to - 32 ^ (3/5)

hjlf

The answer is -8

This was too easy

6 0

2 years ago