Remember that the general decay equation is:
where
is the amount after a time
is the initial amount
is the the decay percent in decimal form
The first ting we are going to do is find
by dividing our <span>decay rate of 25% by 100%: </span>
.
We also know from our problem that
. Lets replace
and
in our formula:
We know now that our decay rate is 0.75, and since 0.75<1, we can conclude that
this situation represents exponential decay.
Now, to find the initial amount, we are going to solve our equation for
:
Notice that
will depend on the number of ours
. <span />
Answer:
(m+2)(m-2)=m^2-4
Step-by-step explanation:
(m+2)(m-2)=m(m-2)+2(m-2)
=m^2-2m+2m-4
=m^2-4
Answer:
f(-2)=4+6+2
f(-2)=12
Step-by-step explanation:
Add -2 where all the x values are then solve
A <span>counterclockwise rotation of 270º about the origin is equivalent to a </span><span>clockwise rotation of 90º about the origin.
Given a point (4, 5), the x-value, i.e. 4 and the y-value, i.e. 5 are positive, hence the point is in the 1st quadrant of the xy-plane.
A clockwise rotation of </span><span>90º about the origin of a point in the first quadrant of the xy-plane will have its image in the fourth quadrant of the xy-plane. Thus the x-value of the image remains positive but the y-value of the image changes to negative.
Also the x-value and the y-value of the original figure is interchanged.
For example, given a point (a, b) in the first quadrant of the xy-plane, </span><span>a counterclockwise rotation of 270º about the origin which is equivalent to a <span>clockwise rotation of 90º about the origin will result in an image with the coordinate of (b, -a)</span>
Therefore, a </span><span>counterclockwise rotation of 270º about the origin </span><span>of the point (4, 5) will result in an image with the coordinate of (5, -4)</span> (option C)
