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GrogVix [38]
2 years ago
11

There is 4 squares and 6 circles. What is the simples ratio of squares to circles?

Mathematics
1 answer:
Charra [1.4K]2 years ago
5 0

Answer:

2:3

Step-by-step explanation:

If you divide 4 by 2 you get 2. If you divided 6 by 2 you get 3. You can't get no more further than that so 2:3 is the simplest ratio.

Hope it helps! :)

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6. What is the Greatest Common Factor of 45<br> and 60?<br> 14560
bazaltina [42]

Answer:

15  15 goes into 45 5 times and 60 5 times. highest number that goes into both numbers evenly

5 0
3 years ago
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The length of a rectangle is 3 inches more than its width. If the perimeter is 42 inches, find the dimensions of the rectangle.​
aalyn [17]

P = 2w + 2l where w is the width, and l is the length. We know the length (l) is 3 inches longer than it's width (or l = w+3). Substitute w +3 into Perimeter equation. P = 2w + 2(w+3).

8 0
2 years ago
It costs $74 per hour plus a $65 service fee to have a home theater system set up for you. Let t represent the number of hours.
ki77a [65]

Answer:

74t + 65= total cost

Step-by-step explanation:

74 is the amount per hour, so you would need to multiply that by the number of hours they work (74t) and the 65 is a set fee (does not change based on the amount of service) so you just add that on

8 0
2 years ago
*LAST QUESTION, PLEASE HURRY AND ANSWER* What is the volume of the cone below? (Use 3.14 for pi)
enyata [817]

Answer:

<h2>           The third:  5.32 cubic units</h2>

Step-by-step explanation:

R = 1.52

H = 2.2

π = 3.14

V=\frac13\pi R^2\cdot H\\\\V=\frac13\cdot3.14\cdot(1.52)^2\cdot2.2=5.3200810\overline6\approx5.32

4 0
3 years ago
A simple random sample of size nequals10 is obtained from a population with muequals68 and sigmaequals15. ​(a) What must be true
valentina_108 [34]

Answer:

(a) The distribution of the sample mean (\bar x) is <em>N</em> (68, 4.74²).

(b) The value of P(\bar X is 0.7642.

(c) The value of P(\bar X\geq 69.1) is 0.3670.

Step-by-step explanation:

A random sample of size <em>n</em> = 10 is selected from a population.

Let the population be made up of the random variable <em>X</em>.

The mean and standard deviation of <em>X</em> are:

\mu=68\\\sigma=15

(a)

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Since the sample selected is not large, i.e. <em>n</em> = 10 < 30, for the distribution of the sample mean will be approximately normally distributed, the population from which the sample is selected must be normally distributed.

Then, the mean of the distribution of the sample mean is given by,

\mu_{\bar x}=\mu=68

And the standard deviation of the distribution of the sample mean is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{15}{\sqrt{10}}=4.74

Thus, the distribution of the sample mean (\bar x) is <em>N</em> (68, 4.74²).

(b)

Compute the value of P(\bar X as follows:

P(\bar X

                    =P(Z

*Use a <em>z</em>-table for the probability.

Thus, the value of P(\bar X is 0.7642.

(c)

Compute the value of P(\bar X\geq 69.1) as follows:

Apply continuity correction as follows:

P(\bar X\geq 69.1)=P(\bar X> 69.1+0.5)

                    =P(\bar X>69.6)

                    =P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{69.6-68}{4.74})

                    =P(Z>0.34)\\=1-P(Z

Thus, the value of P(\bar X\geq 69.1) is 0.3670.

7 0
3 years ago
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