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vladimir1956 [14]
3 years ago
7

How do you change a improper fraction to a mixed number?

Mathematics
1 answer:
Dima020 [189]3 years ago
6 0
Divide the numerator by denominator
23÷4=5 (3/4)
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A board game has a spinner divided into sections of equal size. Each section is labeled with a number between 1 and 5. Which num
Valentin [98]

Answer:

75

Step-by-step explanation:

first, there are three 5's on the spinner, with a total of 12 sections. 3/12 = 0.25, so you multiply 0.25 times 300 (the total spins) and get 75

3 0
3 years ago
your friend is choosing between two music download companies. MyTunes charges $2.50 per song. Great Songs charges $1.50 per song
vichka [17]

Answer:

After 100 songs

Step-by-step explanation:

2.50x=1.50x+50

.50x=50

÷.50

X=100

4 0
3 years ago
Write 125 as a product of primes. Use index notation when giving your answer.
Mnenie [13.5K]

Answer:

5^3

Step-by-step explanation:

125= 5*25

25=5*5

5 is a prime number and there are 3 of them so the answer in index notation will be 5^3

3 0
3 years ago
Please Help! Solve the equation for x.
SOVA2 [1]

Answer:

A

Step-by-step explanation:

Given

\frac{1}{3} x - 8 = - 12 ( multiply through by 3 to clear the fraction )

x - 24 = - 36 ( add 24 to both sides )

x = - 12 → A

6 0
3 years ago
Please Help. 25 points. <br>​
vodomira [7]

Answer:

\boxed{x = 7, y = 9, z = 68}

Step-by-step explanation:

We must develop three equations in three unknowns.

I will use these three:

\begin{array}{lrcll}(1) & 8x + 13y +7 & = & 180 & \\(2)& 9x - 7 + 13y +7 & = & 180 & \\(3)& 8x + 5y - 11 + z & = & 180 &\text{We can rearrange these to get:}\\(4)& 8x + 13y & = & 173 &\\(5) & 9x + 13y & = & 180 & \\(6)& 8x + 5y + z & = & 169 & \\(7)& x & = & \mathbf{7} & \text{Subtracted (4) from (5)} \\\end{array}

\begin{array}{lrcll}& 8(7) + 13y & = & 173 & \text{Substituted (7) into (4)} \\& 56 + 13y & = & 173 & \text{Simplified} \\& 13y & = & 117 & \text{Subtracted 56 from each side} \\(8)& y & =& \mathbf{9}&\text{Divided each side by 13}\\& 8(7) + 5(9) + z & = & 169 & \text{Substituted (8) and (7) into (6)} \\& 56 + 45 + z& = & 169 & \text{Simplified} \\& 101 + z& = & 169 & \text{Simplified} \\&z& = & \mathbf{68} & \text{Subtracted 101 from each side}\\\end{array}

\boxed{\mathbf{ x = 7, y = 9, z = 68}}

4 0
3 years ago
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