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3 years ago

Explain how the number of pieces in a whole relates to the size of each piece

Mathematics

2 answers:

BaLLatris [955]3 years ago

6 0

The more pieces you have the smaller they will be ? I hope that helps

anyanavicka [17]3 years ago

4 0

The more pieces you have an a hole the smaller the pieces will be the last pieces you have been a whole big are the pieces will be

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What is 3550/5 as a regular fraction

anastassius [24]

Answer:

it can not be made into a regular fraction. but it can be made into a whole number. the whole number would be 710

Step-by-step explanation:

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4 years ago

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IceJOKER [234]

Answer:

a = 115°, alternate interior angles are congruent
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Calculus: Can anyone help me on this?

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3 years ago

Given the functions k(x) = 2x2 − 7 and p(x) = x − 4, find (k ∘ p)(x).

Fynjy0 [20]

For this case we have the following functions:

$k (x) = 2x ^ 2-7\\p (x) = x-4$

We must find $(k_ {0} p) (x)$ . By definition of compound functions we have to:

$(k_ {0} p) (x) = k (p (x))$

So:

Taking into account that:

$(a-b) ^ 2 = a ^ 2-2ab + b ^ 2$

Different signs are subtracted and the major sign is placed.

$k (p (x)) = 2 (x-4) ^ 2-7 = 2 (x ^ 2-2 (x) (4) + 4 ^ 2) -7 = 2 (x ^ 2-8x + 16) -7 = 2x ^ 2-16x + 32-7 = 2x ^ 2-16x + 25$

Finally we have to:

$(k_ {o} p) (x) = 2x ^ 2-16x + 25$

Answer:

$(k_ {o} p) (x) = 2x ^ 2-16x + 25$

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3 years ago

A guy wire is attached to the top of a radio antenna and to a point on horizontal ground that 40 m from the base of the antenna.

frutty [35]

Answer:

The length of the wire is 76.19 m.

Step-by-step explanation:

It is given that a guy wire is attached to the top of a radio antenna and to a point on horizontal ground that 40 m from the base of the antenna.

It means base of the right angled triangle is 40 m.

The wire makes an angle of 58deg 20min with the ground.

1 degree = 60 min

Using this conversion convert the given angle in degree.

$58^{\circ}20'=58^{\circ}\frac{20}{60}^{\circ}=58\frac{1}{3}^{\circ}=\frac{175}{3}^{\circ}$

In a right angled triangle

$\cos \theta=\frac{adjacent}{hypotenuse}$

$\cos (\frac{175}{3}^{\circ})=\frac{40}{hypotenuse}$

$0.525=\frac{40}{hypotenuse}$

$hypotenuse=\frac{40}{0.525}$

$hypotenuse=76.190$

Therefore the length of the wire is 76.19 m.

3 0

3 years ago