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Rom4ik [11]
4 years ago
13

What is the correct way to figure out how much gas a car needs to go one mile if it gets 51 miles per gallon ?

Mathematics
1 answer:
8090 [49]4 years ago
5 0

Answer:

5.78 gallons of gas

Step-by-step explanation:


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Simplify seven square root of three end root minus four square root of six end root plus square root of forty eight end root min
Cloud [144]

7\sqrt{3}- 4\sqrt{6} + \sqrt{48} - \sqrt{54} simplified as 11\sqrt{3}- 7\sqrt{6} or 1.909 .

<u>Step-by-step explanation:</u>

We need to Simplify seven square root of three end root minus four square root of six end root plus square root of forty eight end root minus square root of fifty four. Which is equivalent to 7\sqrt{3}- 4\sqrt{6} + \sqrt{48} - \sqrt{54} :

7\sqrt{3}- 4\sqrt{6} + \sqrt{48} - \sqrt{54}

⇒ 7\sqrt{3}- 4\sqrt{6} + \sqrt{48} - \sqrt{44}

⇒ 7\sqrt{3}- 4\sqrt{6} + \sqrt{16(3)} - \sqrt{9(6)}

⇒ 7\sqrt{3}- 4\sqrt{6} + 4\sqrt{(3)} - 3\sqrt{(6)}

⇒ 11\sqrt{3}- 4\sqrt{6}- 3\sqrt{(6)}

⇒ 11\sqrt{3}- 7\sqrt{6}

\sqrt{3} = 1.732 , \sqrt{6} = 2.449

⇒ 11(1.723)- 7(2.449)

⇒ 1.909

Therefore, 7\sqrt{3}- 4\sqrt{6} + \sqrt{48} - \sqrt{54} simplified as 11\sqrt{3}- 7\sqrt{6} or 1.909 .

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3 years ago
HElP- also if u r wondering teh answer is NOT 24
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a test consists of 10 multiple choice questions, each with four possible answers. To pass the test, one must answer at least nin
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How to simplify (-2a^2b^-3/a^-4b^-5)^-3 ?
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Fine the mean and range 20 14 29 39 25 19 35
Anika [276]

First to find the mean add up all the numbers

20+14+29+39+25+19+35

which is equal to 181 now divide that number by the amount of numbers in the set, at which there are 7

So divide 181 by 7

181/7=25.86

Now round

So the mean is 26


To find the range subtract the least number from the greatest number

In which the two numbers need here are 14 and 39

39-14=15

So the range is 15

7 0
3 years ago
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