Answer is: it takes 116,8 seconds to fall to one-sixteenth of its initial value
<span>
The half-life for the chemical reaction is 29,2 s and is
independent of initial concentration.
c</span>₀
- initial concentration the reactant.
c - concentration of the reactant remaining
at time.
t = 29,2 s.<span>
First calculate the rate constant k:
k = 0,693 ÷ t = 0,693 ÷ 29,2 s</span> = 0,0237 1/s.<span>
ln(c/c</span>₀) = -k·t₁.<span>
ln(1/16 </span>÷ 1) = -0,0237 1/s ·
t₁.
t₁ = 116,8 s.
Answer:
2-chloro-4-methylpentanal.
Explanation:
Hello there!
In this case, according to the chemical compound:
CH3-CH-CH2-CH-CHO
| |
CH3 Cl
We can see the main functional group is an starting carbonyl, which means this is an aldehyde. Moreover, we can see a Cl-substituent on the second carbon and a methyl substituent on the fourth carbon. Therefore, the IUPAC name turns out: 2-chloro-4-methylpentanal.
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Answer:
1)Na2O
let the valency of Na is x
2(x)+(2)=0
2x+2=0
2x=-2
x=-1
2)ZnO
let the valency of Zn is x
x+2=0
x=-2
3)Al2O3
let the valency of Al is x
2(x)+3(2)=0
2x+6=0
2x=-6
x=-3
4)MgO
let the valency of Mg is x
x+2=0
x=-2
Answer : The products are Silver sulfide, 
and Sodium iodide, 
.
Explanation :
The given balanced chemical reaction is,
From the given balanced reaction, we conclude that the 2 moles of silver iodide react with the 1 mole of sodium sulfide to give product as 1 mole of silver sulfide and 2 moles of sodium iodide.
In a chemical reaction, reactants are represent on the left side of the right-arrow and products are represent on the right side of the right-arrow.
Therefore, in a chemical reaction the products are Silver sulfide and Sodium iodide.
Answer:
204.8g
Explanation:
The number of moles of a substance is related to its mass and molecular mass as follows:
mole (n) = mass (m) ÷ molar mass (MM)
According to this question, 3.50 moles of sodium chloride (NaCl) is added to a food.
Molar mass of NaCl = 23 + 35.5
= 58.5g/mol
Using mole = mass/molar mass
Mass = molar mass × mole
Mass = 58.5g/mol × 3.5mol
Mass = 204.75
Mass = 204.8grams.
Therefore, 204.8grams of NaCl or common salt was added to the food.
