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3 years ago

Several types of radiation may be emitted during radioactive decay. The equation represents

Physics

2 answers:

vovangra [49]3 years ago

7 0

Answer:

The equation represents the origin of a beta particle from the nucleus of an atom. Beta particles are fast moving electrons; they have a negative charge and originate when a neutron decomposes into a protons, which remains behind in the nucleus, and an electron.

Explanation:

Fittoniya [83]3 years ago

5 0

I think the answer is B

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What is pitch related to in terms of sound? Does it affect the speed? If so, how?

Juli2301 [7.4K]

Pitch is the impression the listener gets of the <em>frequency</em> of the sound.

The speed of the sound is <em>not</em> related to its pitch/frequency.

If the speed and frequency were related, that would be a real problem. Bands, orchestras, and choirs could not exist ! All the instruments in the orchestra could play a note together, at the same time. But then the higher instruments ... the flute, trumpet, violins, high guitar strings and high piano keys ... would travel to you fast, and the lower instruments ... the trombone, tuba, double bass, bass drum, low guitar strings and the low piano keys ... would travel to you slow. They all played the note at the same time, but by the time you heard it, it would be all smeared out ... every instrument arriving at your ear at a different time !

5 0

4 years ago

A punter drops a 2.0 kg ball from rest vertically 1 meter down onto his foot. The ball leaves the foot with a speed of 18 m/s at

pav-90 [236]

Answer:

Explanation:

Given

mass of drop $m=2 kg$

height of fall $h=1 m$

ball leaves the foot with a speed of 18 m/s at an angle of $55^{\circ}$

Velocity of ball just before the collision with the floor

$u^=2gh$

$u=\sqrt{2gh}$

$u=\sqrt{2\times 9.8\times 1}=4.42 m/s$

Impulse delivered in Y direction

$J_y=m(v\sin (55)-(-u))$

$J_y=2(18\sin (55)+4.42)$

$J_y=38.32 kg-m/s$

Impulse in x direction

$J_x=m\times v\cos (55)$

$J_x=2\times 4.42\cos (55)=20.646$

$J_{net}=\sqrt{J_x^2+J_y^2}$

$J_{net}=\sqrt{(38.32)^2+(20.64)^2}$

$J_{net}=43.52 kg-m/s$

at an angle of $\tan \phi =\frac{J_y}{J_x}=\frac{38.32}{20.64}$

$\phi =tan^{-1}(1.856)$

$\phi =61.7^{\circ}$

7 0

3 years ago

A 1-pound ball and a 100-pound ball are dropped from a height of 10 feet at the same time. in the absence of air resistance, ___

Elena L [17]

The 100 ball would fall faster

7 0

3 years ago

Read 2 more answers

What is the speed of light (f = 5.09 E14 Hz) in glycerol?

Vikentia [17]

Answer:

The speed of light in glycerol is 2.04×108 m/s .

Explanation:

4 0

2 years ago

5. Principal Rodriguez has asked all students exit the building by 2:45 pm! If you want to exit

Kryger [21]

With the Pythagoras Theorem we can find that the distance traveled is:

39 m

The distance is the length of the path between two points and it is a scalar magnitude so if the path changes direction the Pythagorean theorem should be used

d = $\sqrt{(x-x_o)^2 + (y-y_o)^2 + (z-z_o)^2 }$

Where d is the distance, (x,y,z) is the interes point, (x₀,y₀,z₀) is de reference point.

In this case, let's set a reference system in the lower part of the school, take the z-axis as vertical and set the point of arrival at as the reference (0, 0, 0).

The distance that the students descend is d₁ = 30 k ^ m, when they arrive from the bottom of the school they travel d₂ = 15 j ^ m and d₃ = 20 i ^ m

let's calculate

d = $\sqrt{(20-0)^2 + (15-0)^2 + ( 30-0)^2 }$

d = 39.05 m

Notice that the distance by being a scalar does not have unit vectors

In conclusion using the Pythagoras Theorem we can find that the distance traveled is 39 m

Learn more about distance here:

brainly.com/question/7942332

3 0

3 years ago