Ask question

Ask question

All categories

iogann1982 [59]

3 years ago

12

Several types of radiation may be emitted during radioactive decay. The equation represents

2 answers:

vovangra [49]3 years ago

7 0

Answer:

The equation represents the origin of a beta particle from the nucleus of an atom. Beta particles are fast moving electrons; they have a negative charge and originate when a neutron decomposes into a protons, which remains behind in the nucleus, and an electron.

Explanation:

Fittoniya [83]3 years ago

5 0

I think the answer is B

You might be interested in

Students will explain, distinguish the difference between the 4 states of matter

vitfil [10]

What? what what what what

7 0

3 years ago

Which statements describe density? Check all that apply.

HACTEHA [7]

Density is a chemical property of an object.

The density of an object is constant.

Density is a derived unit of measure

7 0

3 years ago

Read 2 more answers

if an object 18mm high is placed 12mm from a diverging lens and the image is formed 4mm in front of the lens what is the height

brilliants [131]

To solve this problem we use an amplification formula for divergent lenses

$M = \frac{i}{o} = \frac{h'}{h}$

Where:

i: distance of the image to the lens

o: Distance from the object to the lens

h = height of the object

h '= height of the image

$M = \frac{4mm}{12mm} = \frac{h'}{18mm}$

$h'= 18mm\frac{4mm}{12mm}$

h '= 6 mm

The height is 6 mm

5 0

3 years ago

Two circular coils are concentric and lie in the same plane. The inner coil contains 170 turns of wire, has a radius of 0.012 m,

GREYUIT [131]

Answer:

The current of the outer coil is $I_o = 3.99 \ A$

Explanation:

From the question we are told that

The number of turns of the inner coil is $N_i = 170 \ turn$

The radius of the inner coil is $R_i = 0.012 \ m$

The current of the inner coil is $I_i = 6.2 \ A$

The number of turns of the outer coil is $N_o = 220 \ turns$

The radius of the outer coil is $R_o = 0.02 0 \ m$

Generally the net magnetic field is mathematically represented as

$B = \frac{N \ mu I }{ 2 * R }$

Now from told that the net magnetic field is common

So

$\frac{N_i \mu I_i} {2 * R _i} = \frac{N_o \mu I_o} {2 * R _o}$

Here $\mu$ is the permeability of free space

making $I_o$ the subject

$I_o = \frac{ N_i I_i *2 * R _o}{N_o *2 * R _i}$

substituting values

$I_o = \frac{ 170 *6.2 *2 * 0.020}{220 *2 * 0.012}$

$I_o = 3.99 \ A$

5 0

3 years ago

Solve the given parallel circuit by computing the desired quantities.

Alex Ar [27]

Hope this provides some answers

7 0

3 years ago