Answer:
I think it would most likely be 2... but not so sureee
Is their a paper for this...Thats all you have to do is read it....I will help if you put a pic of the paper.
Answer:
The acceleration of the car is
Explanation:
We are assuming rightward coordinate positive and all quantities are along this direction
We know,
where a - acceleration, v=velocity, t=time and x=displacement
multiply by dx in both sides
but we know
Therefore,
Here we integrate both sides with proper limits
x ranges from 0 to 110 as v ranges from 29 to 34
p = 0, r = 110, q = 29, s = 34
a is given as constant thus can be pulled out of the integration
Therefore,
Accelaration of the car is
Note:
Here moving to the right doesn't mean anything significant other than the fact that all quantities are pointing in that direction. Therefore obtained acceleration is also towards the right
If you know equation of motion for constant acceleration as
you can plug in values in this equation to obtain value of a
v - final velocity
u - initial velocity
s - displacement
Answer:
Angular acceleration = 5 rad /s ^2
Kinetic energy = 0.391 J
Work done = 0.391 J
P =6.25 W
Explanation:
The torque is given as moment of inertia × angular acceleration
angular acceleration = torque/ moment of inertia
= 10/2= 5 rad/ s^2
The kinetic energy is = 1/2 Iw^2
w = angular acceleration/time
=5/8= 0.625 rad /s
1/2 × 2× 0.625^2
=0.391 J
The work done is equal to the kinetic energy of the motor at this time
W= 0.391 J
The average power is = torque × angular speed
= 10× 0.625
P = 6.25 W
Increase the change in momentum of the collision